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ohaa
3 months ago
7

Three balls of equal mass are fired simultaneously with equal speeds from the same height h above the ground. Ball 1 is fired st

raight up, ball 2 is fired straight down, and ball 3 is fired horizontally. Rank in order from largest to smallest the speeds of the balls, v1, v2, and v3, just before each ball hits the ground. a. v1 > v2 > v3 b. v3 > v2 > v1 c. v2 > v3 > v1 d. v1 = v2 = v3
Physics
1 answer:
Ostrovityanka [3.2K]3 months ago
4 0

Answer:

d) v1 = v2 = v3

Explanation:

This can be determined through the principle of energy conservation. We assess the total mechanical energy E=K+U (the sum of kinetic energy and gravitational potential energy) at both the initial and final positions, ensuring they remain constant.

<pInitially, for the three spheres, we have:

E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh

Finally, for the three spheres, we see:

E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}

<pGiven that E_i=E_f, and since E_i remains identical for all spheres, it follows that E_f is identical for all spheres, indicating that v_f, the final velocity, is equal for each ball.
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The body’s mass is 25 g, which converts to 0.025 kg (since 1 kg = 1000 g).

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Oscillations per second = \frac{20}{4}=5

Spring's frequency of vibration is = 5 s^{-1}=5 Hz

The spring constant 'k' can be derived from the relationship involving frequency, mass, and spring constant.

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Which of the following combinations of variables results in the greatest period for a pendulum? length = L, mass = M, and maximu
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Clarification:

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To tackle this question, we know the following:

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According to the information provided in the question,

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T = \frac{h}{H_O \alpha_{steel} } + T_O

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