The answer is
-Small f and large D.
The explanation:
-A car jack acts as a machine, defined as an apparatus that aids individuals in exerting force more easily.
-Hence, by applying a small force to the jack, the height at which the car is elevated increases.
Machines are essential for people to amplify their strength; without them, lifting a car would be impossible.
Employing leverage or hydraulic principles, machines enhance your exerted force.
Utilizing a greater lever allows for extensive movement with minimal force, resulting in the opposite side moving shorter distances with an increased force.
Answer:
The response to your inquiry is: 15 m/s²
Explanation:
Equation x = at³ - bt² + ct
a = 4.1 m/s³
b = 2.2 m/s²
c = 1.7 m/s
First we calculate x at t = 4.1 s
x = 4.1(4.1)³ - 2.2(4.1)² + 1.7(4.1)
x = 4.1(68.921) - 2.2(16.81) + 6.97
x = 282.58 - 36.98 + 6.98
x = 252.58 m
Now we calculate speed
v = x/t = 252.58/ 4.1 = 61.6 m/s
Finally
acceleration = v/t = 61.6/4.1 = 15 m/s²
(6-16)/4.0=-2.5 m/s²
The car's acceleration is -2.5 m/s²
The duration required for the seventh car to pass amounts to 13.2 seconds. The train's movement is characterized by uniform acceleration, enabling the application of suvat equations. Initially, we analyze the movement of the first car, utilizing the equation for distance s covered in time t, which corresponds to the length of one car, with u = 0 as the initial velocity and a representing acceleration, over t = 5.0 s. We can rearrange the equation reflecting L as the length of one car. This is similarly applicable for the initial seven cars, accounting for the distance of 7L and the required time t'. With constant acceleration retained, we can derive t' through substitution in the equation, leading to fundamental conclusions regarding the relationship exhibited in the graph of distance against time in uniformly accelerated motion.
