Dolls = d
trains = t
8d + 10t = 150
I believe we can express it like that.
The provided function is:
P = 0.04x + 0.05y + 0.06(16-x-y)
To determine the function's value at each vertex, simply plug in the respective x and y coordinates into the equation to find the value of P as shown below:
1- For (8,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(8) + 0.05(1) + 0.06(16-8-1)
P = 0.79
2- For (14,1):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(14) + 0.05(1) + 0.06(16-14-1)
P = 0.67
3- For (3,6):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(3) + 0.05(6) + 0.06(16-3-6)
P = 0.84
4- For (5,10):
P = 0.04x + 0.05y + 0.06(16-x-y)
P = 0.04(5) + 0.05(10) + 0.06(16-5-10)
P = 0.76
I hope this is useful:)
Response:
∠PQL=∠TRN [Angles corresponding]
Thus, PQ║RS and PQ=RS
Detailed explanation:
The side PQ has been drawn.
A second side QR is traced, forming an acute angle with side PQ.
Now side QR is extended to the left.
Create an arc from point Q such that it intersects QP at M and extends RQ at L. Without altering the compass width (i.e., the distance between the nib and pencil), draw an arc from R to intersect RQ at N. Now measure the distance LM with a compass. Position the compass at N and mark an arc cut from point R. Designate this intersection as T. Draw a line from point R through T. Then measure the length of PQ with the compass. Position your compass at R and create an arc on the produced line RT at S. Thus, we ascertain that PQ║RS and PQ=RS.
This occurs because
∠MQL=∠NRT [corresponding angles, with QR acting as the transversal]
∵PQ║RS and PQ=RS [This identifies PQRS as a parallelogram]
Out of the four students who illustrated their explanations
Student 2 presented a partially correct but valid explanation.
