Milton is floating in an inner tube in a wave pool. He is 1.5 m from the bottom of the pool when he is at the trough of a wave.

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Milton is floating in an inner tube in a wave pool. He is 1.5 m from the bottom of the pool when he is at the trough of a wave.

A stopwatch starts timing at this point. In 1.25 s, he is on the crest of the wave, 2.1 m from the bottom of the pool. a) Determine the equation of the function that expresses Milton's distance from the bottom of the pool in terms of time.

Mathematics

1 answer:

lawyer [12.5K] · Answer 1 · 2026-04-04T23:04:00+03:00

To tackle this sinusoidal question, we begin with the following: Using the formula; g(t)=offset+A*sin[(2πt)/T+Delay] According to sinusoidal theory, the duration from trough to crest is typically half of the wave's period. Here, T=2.5 The peak magnitude is calculated as: Trough-Crest=2.1-1.5=0.6 m amplitude=1/2(Trough-Crest)=1/2*0.6=0.3 The offset from the center of the circle becomes 0.3+1.5=1.8 As the delay is at -π/2, the wave will commence at the trough at [time,t=0]. Plugging these values into the formula gives: g(t)=1.8+(0.3)sin[(2*π*t)/2.5]-π/2] g(t)=1.8+0.3sin[(0.8πt)/T-π/2]