Answer:
7 years
Step-by-step explanation:
Since a graph isn’t provided, I will indicate how many years are involved, and you should be able to deduce it from this. First, let’s [use a calculator] to find 2% of 250, which equals 5. Adding 5 to the total only slightly impacts 2% of the original amount, changing it by 0.1 or 5/50. We can continue adding 5 until we exceed 282, which occurs after 7 increments, calculated as (285 minus 250) divided by 5. Thus, the answer is indeed 7 years. A quick calculation will confirm this.
According to the graph, which depicts a parabola, we can determine that the function will be quadratic. First, we identify the zeros as x=2 and x=4. Next, we can form the function using a point to solve for 'a'. For instance, at x=3 and y=-3, we can find 'a.' Plugging back into the equation, we can perform necessary multiplications to reach the final function.
Answer: refer to the image
Step-by-step explanation:
Answer:
The answer is the scatter plot that displays a pronounced positive slope along the curve of best fit.
Step-by-step explanation:
A scatter plot illustrates the relationships between two variables for an individual. It is essentially a graph in which a best-fit curve is drawn to encapsulate the complete dataset. A scatter plot is considered to have a robust correlation if the correlation coefficient is near r = 1, indicating a very strong connection between the two variables.
A scatter plot exhibits a solid correlation when its data points are closely aligned to the line or curve of best fit.
For r = 1, the correlation is regarded as strong and positive.
c) Step-by-step breakdown: The collision rate is 1.2 incidents per 4 months, which can be expressed as 0.3 incidents monthly. Therefore, the Poisson distribution for the variable X representing monthly collisions is defined as P(X = x) =... for x ∈ N ∪ {0} = 0 otherwise. (1) Where X = 0 denotes no collisions during a 4-month timeframe, substituting gives P(X = 0) =... (2). For a 4-month period, P(No collision in 4 month period) =... (3). Two collisions in a 2-month span translate to 1 per month, thus P(X =1) =... (4). Over 2 months, P(2 collisions in a 2 month period) =... (5). One collision over a 6-month period equates to P(1 collision in 6 months period) =... (6). Consequently, P(1 collision in 6 month period) results in... (7). For no collisions in a 6-month period, P(No collision in 6 months period) =... (8). Finally, the probability of 1 or fewer collisions over six months is P(1 or fewer collision in 6 months period) = (8) + (7) = 0.0785 + 0.1653.