1
2
3
Step-by-step explanation: Generally, during the roll of two fair 6-sided dice, the doubles result in (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6). Therefore, the total for doubles is N = 6. The outcome of rolling two fair 6-sided dice yields n = 36. Thus, the probability of rolling doubles (matching numbers on both dice) is calculated mathematically. When rolling two fair dice, outcomes that sum to 4 or less are (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1). Observing this, we see two doubles present. Consequently, the conditional probability of rolling doubles is represented mathematically. Lastly, when rolling the two fair dice, outcomes that show different numbers result in L = 30, while outcomes where at least one die shows a 1 give W = 10. Hence, the conditional probability of having at least one die show a 1 is presented mathematically.
Answer:
Part A. At least 6 hours
Part B. In less than 2.5 hours, Elijah will fall behind Mercedes
Part C. In over 2.5 hours, Elijah will lead Aubrey
Step-by-step explanation:
D = distance
v = speed
t = time
Formula connecting D, v, and t:

Part A.
Steve's speed: 
Distance: a minimum of 21 miles
Time: unknown, so
![3.5\cdot t\ge 21\\ \\35t\ge 210\ [\text{Multiplied by 10}]\\ \\t\ge \dfrac{210}{35}\\ \\t\ge \dfrac{30}{5}\\ \\t\ge 6](https://tex.z-dn.net/?f=3.5%5Ccdot%20t%5Cge%2021%5C%5C%20%5C%5C35t%5Cge%20210%5C%20%5B%5Ctext%7BMultiplied%20by%2010%7D%5D%5C%5C%20%5C%5Ct%5Cge%20%5Cdfrac%7B210%7D%7B35%7D%5C%5C%20%5C%5Ct%5Cge%20%5Cdfrac%7B30%7D%7B5%7D%5C%5C%20%5C%5Ct%5Cge%206)
It would require Steve a minimum of 6 hours to traverse at least 21 miles on Day 1.
Part B.
Mercedes's speed: 
Elijah's speed: 
Elijah's Distance walked:
miles
Mercedes's Distance walked:
miles
Time: x hours
Mercedes is 2 miles ahead, therefore

Elijah will trail behind until

In 2.5 hours, Elijah will close the gap on Mercedes, and in less than 2.5 hours, Elijah will trail behind her.
Part C.
Aubrey's speed: 
Elijah's speed: 
Elijah's Distance walked:
miles
Aubrey's Distance walked:
miles
Time: x hours
At the beginning of Day 3, Elijah starts from Mile 42, while Aubrey begins at Mile 42.5.

Elijah will be ahead of Aubrey when
![D_E>D_A\\ \\42+3.2x> 42.5+3x\\ \\3.2x-3x>42.5-42\\ \\0.2x>0.5\\ \\2x>5\ [\text{Multiplied by 10}]\\ \\x>\dfrac{5}{2}\\ \\x>2.5\ hours](https://tex.z-dn.net/?f=D_E%3ED_A%5C%5C%20%5C%5C42%2B3.2x%3E%2042.5%2B3x%5C%5C%20%5C%5C3.2x-3x%3E42.5-42%5C%5C%20%5C%5C0.2x%3E0.5%5C%5C%20%5C%5C2x%3E5%5C%20%5B%5Ctext%7BMultiplied%20by%2010%7D%5D%5C%5C%20%5C%5Cx%3E%5Cdfrac%7B5%7D%7B2%7D%5C%5C%20%5C%5Cx%3E2.5%5C%20hours)
In 2.5 hours, Elijah will surpass Aubrey, and after more than 2.5 hours, Elijah will outpace Aubrey.
Answer:
The price amounts to $9.70 per kilogram.
Step-by-step explanation:
This can be resolved using the rule of three.
In a rule of three scenario, the first step involves determining how the values are related, whether directly or inversely.
A direct relationship implies that when one measure increases, the corresponding measure also increases. In this case, cross multiplication serves as the method for the rule of three.
Alternatively, an inverse relationship indicates that an increase in one measurement causes a decrease in the other. In this scenario, line multiplication applies.
Here, the relationship is between the weight of the cheese and its cost. As the weight rises, so does the expense, representing a direct proportion.
Solution:
According to the problem, cheese is priced at $4.40 per pound. Given that each kg equals 2.2 pounds, we can deduce how many kg correspond to one pound.
1 pound - x kg
2.2 pounds - 1 kg


kg
Given that cheese costs $4.40 for a pound, and there are 0.45 kg in one pound, we calculate the cost for 1 kg.
$4.40 - 0.45 kg
$x - 1 kg



The price is $9.70 per kilogram.
Every square meter of ceiling needs 10.75 tiles. To calculate the number of tiles needed for various ceiling areas: For a ceiling area of 1, it requires 10.75 tiles. For a ceiling area of 10, it requires 10.75 × 10, which equals 107.5 tiles. For an area of 100, it needs 10.75 × 100, totaling 1075 tiles. Consequently, that represents the necessary solution.