If tap and bre are supplementary and bre is its own complement, find the measure of tap. explain how you arrived at your answer

Respuesta:

la cantidad de elemento restante después de 14 minutos = 7.091 g =~ 10 g

Explicación paso a paso:

Después de cada minuto, la cantidad que queda será

(100 - 26.9) % es decir, 73.1 %

lo que equivale a 0.731 veces la cantidad inicial.

Si el tiempo transcurrido se representa como t, la función f(t) indica la masa del elemento restante, nuestra ecuación será

f(t) = 570(0.731) ^ t

t= 14 minutos

f(14) = 570 (0.731) ^ 14

= 7.091 g =~ 10 g

Answer:

We will mix 2.4 mL of water with 0.6 mL of the coloring solution.

The total solution volume amounts to 2.4 + 0.6, which equals 3 mL.

Therefore,

0.6 mL of coloring solution now contains 2.4 mL of water.

Alternatively,

1 mL of this coloring solution comprises 4 mL of water.

Thus,

We should prepare 3 mL of the coloring solution with the resultant water.

This 3 mL mixture will encapsulate 0.6 mL of the coloring solution.

Step-by-step explanation:

As stated:

The formula requires 0.6 mL of a coloring solution.

Using a 10-mL graduated cylinder that is divided from 2 to 10 mL in 1-mL increments:

We aim to apply the aliquot method to accurately measure 0.6 mL of the coloring solution.

Given that the graduated cylinder measures from 2mL to 10mL only, we'll blend 2.4 mL of water with 0.6 mL of coloring solution.

Thus, the total solution volume is 2.4 + 0.6, resulting in 3 mL.

Consequently,

This implies that 0.6 mL of coloring solution now carries 2.4 mL of water.

Additionally,

1 mL of coloring solution encapsulates 4 mL of water.

Hence,

We will quantify 3 mL of the final solution, which contains 0.6 mL of coloring solution.

Answer: There exists a distinction between rote counting and rational counting. Rote counting requires memorizing sequences of numbers, whereas rational counting informs children about "how many items there are." For children to engage in rational counting, they must exhibit one-to-one correspondence.