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pshichka
3 months ago
15

must a function that is decreasing over a given interval always be negative over that same interval explain

Mathematics
2 answers:
lawyer [12.5K]3 months ago
8 0

refer to the image provided below.


It’s evident that a function exhibiting a decrease, characterized by a negative slope, does not necessarily have to have negative values.

lawyer [12.5K]3 months ago
7 0

Response:

no

Detailed explanation:

For a function to decrease in a specific interval, its outputs diminish as the inputs increase; however, those outputs could either be negative or positive. Conversely, for a function to be termed negative across an interval, all outputs must be negative, although the inputs may be either positive or negative.

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Which equation could be used to find the length of the hypotenuse ?
Inessa [12570]
The Pythagorean theorem is a foundational principle. Given that 2 and 5 represent the lengths of the legs while c denotes the hypotenuse, the relevant equation would be stated as such, corresponding to the first option.
3 0
2 months ago
Read 2 more answers
At what rate would you need to invest $12000 and make $2880 after 8 years?
PIT_PIT [12445]

Answer:

3\%

Step-by-step explanation:

We start with the fact that

The formula for simple interest is represented by

I=P(rt)

where:

I denotes the Final Interest Value

P indicates the Principal amount to be invested

r specifies the interest rate

t refers to the Number of Time Periods

For this scenario, we have

t=8\ years\\ P=\$12,000\\I=\$2,880\\r=?

We can substitute these values into the formula mentioned above

2,880=12,000(8r)

Next, we solve for t

2,880=96,000(r)

r=2,880/96,000

r=0.03

Convert to a percentage format

0.03*100=3\%

4 0
3 months ago
The ratio of the loudness of lala's earphones to the loudness of polina's earphones to the loudness of goffy's earphones is 6:5:
PIT_PIT [12445]
Let:
Lala represented as l
Polina represented as P
Goffy represented as G
The ratio for them is 6:5:3
Given that Polina's loudness measures 420 decibels, the total loudness can be computed as follows:
Total ratio=6+5+3=14
Thus, total loudness will be:
14/5×420
=1,176 decibels 
3 0
2 months ago
An old campfire is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount o
PIT_PIT [12445]

During an archaeological excavation, an ancient campfire is uncovered. The charcoal is determined to have significantly less than 1/1000 of the standard amount of ^{14}\text{C} ​. Calculate the minimal age of the charcoal, taking into account that 2^{10} = 1024

Response:

57300 years

Step-by-step breakdown:

Using the relationship of half-life time against fraction, which can be expressed as:

\dfrac{N}{N_o} = (\dfrac{1}{2})^{\frac{t}{t_{1/2}}

In this context,

N indicates the current atom

represents the initial atomN_o

t signifies the time

denotes the half-lifet_{1/2}

Since the charcoal was found to contain less than 1/1000 of the typical amount of ^{14}\text{C} ​.

Thus;

\dfrac{N}{N_o} = \dfrac{1}{1000}

However; the objective is to estimate the minimum age of the charcoal while noting  2^{10} = 1024

this means 2^{10} = 1024, then:

\dfrac{1}{1000}> \dfrac{1}{1024}

\dfrac{1}{1000}> \dfrac{1}{2^{10}}

\dfrac{1}{1000}> (\dfrac{1}{2})^{10}

If

\dfrac{N}{N_o} = \dfrac{1}{1000}

Then

\dfrac{N}{N_o} > (\dfrac{1}{2})^{10}

Consequently, it can be estimated that the minimum time elapsed is 10 half-lives.

For ^{14}\text{C}, the standard half-life time is 5730 years

Thus, the estimation of the minimum age of the charcoal is  5730 years × 10

= 57300 years

5 0
2 months ago
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