Answer:
Step-by-step explanation:
For resolution, the Euclidean division is necessary:
- The polynomial is expressed as 16-2x³-6x²+x+9=-2x³-6x²+x+9
- We will divide this by: 4+3x-2=3x+2 and analyze the remainder
A visual representation of the process is provided
- The remainder is 47/9, hence the value to subtract is 47/9
a) P(identified as explosive) equals P(actual explosive & identified as explosive) + P(not explosive & identified as explosive) = (10/(4*10^6))*0.95+(1-10/(4*10^6))*0.005 = 0.005002363. Thus, the probability that it actually contains explosives given that it's identified as containing explosives is (10/(4*10^6))*0.95/0.005002363 = 0.000475. b) Let the probability of correctly identifying a bag without explosives be a. Therefore, a = 0.99999763, approximately 99.999763%. c) No, even if this becomes 1, the true proportion of explosives will always be below half of the total detected.
Establish a proportion.
8/127=15/x
Cross multiply
8x=1,905
Divide each side by 8
x=238.125
The greatest of the actual distances is 238.125 km.
Hope this clarification helps:)
