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Rasek
7 days ago
10

A triangle drawn on a map has sides that measure 15 cm, 8 cm, and 10 cm. The shortest of the corresponding real-life distances i

s 127 km. Find the longest of the real-life distances.
Mathematics
1 answer:
Inessa [3.9K]7 days ago
5 0

Establish a proportion.

8/127=15/x

Cross multiply

8x=1,905

Divide each side by 8

x=238.125

The greatest of the actual distances is 238.125 km.

Hope this clarification helps:)

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Answer:

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Detailed solution:

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x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

4 0
14 days ago
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AnnZ [3877]

Question:

Which statement is accurate concerning the function’s discontinuities f(x) = \frac{x-5}{3x^2-17x-28}

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D) Gaps are present at (–7, 0) and.

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B) Asymptotes exist at x = 7 and (x = \frac{-4}{3})

Step-by-step explanation:

Given:

f(x) = \frac{x-5}{3x^2-17x-28}

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Identify the correct statement

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Thus, asymptotes are found at (x = \frac{-4}{3}) and x=7

Option B is determined to be correct

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