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Allisa
1 month ago
9

Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is not even

ly divisible by 2.
A. 7/15

B. 1/2

C. 8/15
Mathematics
2 answers:
Leona [12.6K]1 month ago
6 0

The correct option is C.

babunello [11.8K]1 month ago
5 0
Given that the sequence goes odd, even, odd, and even , there is an equal chance of drawing an odd (<span>not divisible by 2) number as there is for drawing an even number, so the correct option is C.

I appreciate you giving me the opportunity to answer your question. I enjoy assisting others as much as I can, so feel free to reach out if my responses are helpful to you. It really matters to me to know that my contributions support someone in the community who is seeking help. If you require additional assistance, you can send me a PM! I do receive many PMs, so it might take some time for me to reply; I apologize for any delays. Thank you for taking the time to read this, and I wish you a wonderful day! ~ brainily user, Lillyxrose
</span>
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Solve the equation for the red variable(C)in R-C=P
Svet_ta [12734]

To isolate C in the equation

R-C=P

start by subtracting P from both sides:

R-C-P = 0

Then, add C to both sides to get:

R-P=C

5 0
3 months ago
Grace invested $5,200 in an account paying an interest rate of 4.6% compounded daily. Assuming no deposits or withdrawals are ma
lawyer [12517]

Answer:

Step-by-step explanation:

This formula is applied when compounding isn’t continuous or occurs less frequently than annually:

A(t)=P(1+\frac{r}{n})^{(n)(t)} where P represents the initial amount invested, r signifies the interest rate as a decimal, n indicates the frequency of compounding per year, and t denotes the duration in years. For our scenario:

P = 5200,

r = 0.046,

n = 365, and

t = 11

A(t)=5200(1+\frac{.046}{365})^{(365)(11)} Consequently,

A(t)=5200(1+.000126)^{4015} A(t) = 5200(1.658408042) leads to

A(t) = $8623.72

8 0
1 month ago
243.875 to nearest tenth, hundredth, ten, and hundred
Inessa [12570]
When rounding 243.875: to the nearest tenth, it becomes 243.9; to the nearest hundredth, it is 243.88; to the nearest ten, it rounds down to 240; and to the nearest hundred, it rounds down to 200. The general rule in rounding states that if the decimal is less than 5, the number remains the same; if it is 5 or more, you round up.
8 0
2 months ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
Svet_ta [12734]

Answer:

Here’s the response provided

Step-by-step explanation:

Referring to the flask diagram, the diameter of the cylinder measures 1 inch and its height (h) is 3 inches. Thus, the radius of the cylinder (r) = diameter / 2 = 1/2 = 0.5 inch

The volume of the cylinder can be calculated as πr²h = π(0.5)² × 3 = 2.36 in³

As for the sphere, its diameter is 4.5 in. Hence, the radius of the sphere R = diameter / 2 = 4.5/2 = 2.25 in

The volume of the sphere is calculated as 4/3 (πR³) = 4/3 × π × 2.25³ = 47.71 in³

The total volume of the flask = Volume of the cylinder  + Volume of the sphere = 2.36 + 47.71 = 50.07 in³

<pWhen the cylinder and the sphere are expanded by a scale factor of 2, the height (h') of the cylinder becomes 3/2 = 1.5 inches and the radius (r') becomes 0.5/2 = 0.025 inches.

The new volume for the cylinder = πr'²h' = π(0.25)² × 1.5 = 0.29 in³

For the sphere, the new radius is R' = 2.25 / 2 = 1.125 in.

The new volume of the sphere = 4/3 (πR'³) = 4/3 × π × 1.125³ = 5.96 in³

Thus, the new volume of the flask = The new volume of the cylinder  + The new volume of the sphere = 0.29 + 5.96 = 6.25 in³

<pThe ratio of the new volume to the original volume = New Volume of the flask / Volume of the flask = 6.25 / 50.07 = 1/8 = 0.125<pThe resulting volume will thus be 0.125 times the original volume

6 0
2 months ago
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