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ZanzabumX
1 month ago
9

The life of a manufacturer's compact fluorescent light bulbs is normal, with mean 12,000 hours and standard deviation 2,000 hour

s. Seth wants to find the probability that a light bulb he purchased from this manufacturer will last no more than 14,500 hours.
How many standard deviations above the mean is 14,500 hours?
Mathematics
2 answers:
Inessa [12.5K]1 month ago
4 0
Mean = 12000
Standard Deviation = 2000

Our task is to determine how many standard deviations 14,500 is from the mean.
This requires us to compute the z-score

A z-score indicates how far a sample value is from the mean in terms of standard deviations. A positive z-score signifies that the sample value exceeds the mean.

The formula for calculating the z-score is = (Sample Value - Mean) / Standard Deviation
Thus,
Z-score = \frac{14500-12000}{2000} =1.25

This indicates that 14,500 is 1.25 standard deviations higher than the mean of 12,000.
zzz [12.3K]1 month ago
3 0

The initial question: "How many standard deviations above the mean is 14,500 hours?"

Response: A. 1.25

The subsequent question: "Referring to the standard normal table, the likelihood that Seth’s light bulb will last no more than 14,500 (P(z ≤ 1.25)) hours is approximately___."

Response: 89%


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Rate at which risk of down syndrome is changing is approximated by function r(x) = 0.004641x2 − 0.3012x + 4.9 (20 ≤ x ≤ 45) wher
zzz [12365]
The risk of down syndrome, in terms of the percentage of births per year, is changing at a rate given by the equation r(x) = 0.004641x² - 0.3012x + 4.9 for the range 20 ≤ x ≤ 45, where x signifies the maternal age at delivery. To derive the risk function as a percentage of births relative to maternal age x, we integrate r(x), leading to the function f(x) = 0.001547x³ - 0.1506x² + 4.9x + c. When x is 30, f evaluates to 0.14%. This means that 0.001547(30³) - 0.1506(30²) + 4.9(30) + c equals 0.14. Solving gives 41.769 - 135.54 + 147 + c = 0.14, which simplifies to c = -53.089. As a result, we establish that f(x) = 0.001547x³ - 0.1506x² + 4.9x - 53.089 for 20 ≤ x ≤ 45. The graph corresponding to this function is illustrated below.
7 0
2 months ago
Which formula can be used to describe the sequence? -2/3,-4,-24,-144...
lawyer [12517]

The formula that describes the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Step-by-step explanation:

The nth-term formula for a geometric sequence is a_{n}=a(r)^{n-1}, where

  • a represents the first term of the sequence
  • r signifies the common ratio between any two consecutive terms
  • r=\frac{a_{2}}{a_{1}} = \frac{a_{3}}{a_{2}}

∵ The sequence is \frac{-2}{3}, -4, -24, -144,.......

∵ The first term is \frac{-2}{3}

∵ The second term is -4

∴ \frac{-4}{\frac{-2}{3}}=6

∵ The third term is -24

∴ \frac{-24}{-4}=6

∵ The fourth term is -144

∴ \frac{-144}{-24}=6

∵  \frac{a_{2}}{a_{1}} = \frac{a_{3}}{a_{2}} =  \frac{a_{4}}{a_{3}} = 6

∴ There is a consistent ratio between two consecutive terms

∴ The sequence qualifies as a geometric sequence

∵ The formula for the nth term of the geometric sequence is a_{n}=a(r)^{n-1}

∵ a = \frac{-2}{3}

∵ r = 6

∴ The equation for the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

The formula that can be employed to outline the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Learn more:

You can explore more about sequences in

8 0
2 months ago
Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0
babunello [11817]
The provided sequences pertain to every x. To determine the series, we start with the specified value a, and the values of both a_n and a_(n+1) are found accordingly. The calculation of the series comes from dividing the preceding value, yielding results for all x.
8 0
1 month ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.
lawyer [12517]

Answer:

x=-2.38

x=-4.62


Step-by-step explanation:

The question is (2x+3)^2+8(2x+3)+11=0

We let u=2x+3, so the equation becomes:

u^2+8u+11=0

Where a=1, b=8, c=11


By applying the quadratic formula, we arrive at:

Quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

Substituting yields: \frac{-8+-\sqrt{(8)^2-4(1)(11)} }{2(1)}\\=\frac{-8+-\sqrt{20} }{2}\\=\frac{-8+-2\sqrt{5} }{2}\\=-4+\sqrt{5}, -4-\sqrt{5} }

We let u=2x+3, thus x calculates to:

u=2x+3\\(-4+\sqrt{5})=2x+3\\x=\frac{-7+\sqrt{5}}{2}=-2.38

and

u=2x+3\\(-4-\sqrt{5})=2x+3\\x=\frac{-7-\sqrt{5}}{2}=-4.62


The solutions to the equation are x=-2.38 (rounded to 2 decimal places) and x=-4.62 (rounded to 2 decimal places)

6 0
1 month ago
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