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asambeis
4 days ago
11

Julio cubes a number then takes the cube root of the result. He ends up with 20. What number did Julio start with

Mathematics
1 answer:
AnnZ [3.8K]4 days ago
6 0

Suppose we designate the number as x.

Julio's initial action is to cube this number, resulting in:

x^3

Next, he calculates the cube root of this value, leading to:

(x^3)^(1/3)

 

When simplified, this becomes:

x^(3/3) = x^1 = x

Since he ends with the value of 20, we conclude:

x = 20

 

<span>Thus, Julio both began and concluded with the number 20.</span>

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Last week, the price of apples at a grocery store was $1.60 per pound. This week, apples at the same grocery store are on sale a
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Answer:

$6.48

Step-by-step explanation:

Initially calculate the 10% discount on $1.60, which results in $1.44. Then multiply $1.44 by 4.5 to find the total, yielding $6.48.

4 0
12 days ago
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Find a vector parametrization of the ellipse centered at the origin in the xy-plane that has major diameter 8 along the x-axis,
zzz [4022]

Answer:

E(t) = [ 4cos(t), 2 sin(t) ]

Step-by-step explanation:

The equation for the ellipse can be represented as:

 (x² ÷ a² ) + (y² ÷ b² ) = 1    Here, a and b symbolize the semi-major and semi-minor axes.

In this specific instance, we have    x²/16 + y²/ 4 = 1

This expression indicates that it follows the form of (x/a)² + (y/b)² =1

Specifically in our case,    x²/16  + y²/4 = 1, which resembles                 sin²α + cos²α = 1.

By setting x = 4 cos(t), we can proceed to calculate y.

Utilizing the equation x²/16  + y²/4 = 1, we find that:

x²/16  + y²/4 = 1   ⇒    (x²  +  4y²) ÷ 16  = 1

Solving for y yields: (x²  +  4y²)  = 16    ⇒  y²  = ( 16 - x²) ÷4

Substituting x = 4 cos(t) gives us y²  =  (16 - 16cos²(t)) ÷ 4, leading to y = √4 (1 - cos²(t)).

Consequently, we have y = 2 sin(t).

Thus, the vector parameterization of the ellipse can be stated as:

E(t) = [ 4cos(t), 2 sin(t) ]

3 0
6 days ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
Svet_ta [4321]

Answer:

Here’s the response provided

Step-by-step explanation:

Referring to the flask diagram, the diameter of the cylinder measures 1 inch and its height (h) is 3 inches. Thus, the radius of the cylinder (r) = diameter / 2 = 1/2 = 0.5 inch

The volume of the cylinder can be calculated as πr²h = π(0.5)² × 3 = 2.36 in³

As for the sphere, its diameter is 4.5 in. Hence, the radius of the sphere R = diameter / 2 = 4.5/2 = 2.25 in

The volume of the sphere is calculated as 4/3 (πR³) = 4/3 × π × 2.25³ = 47.71 in³

The total volume of the flask = Volume of the cylinder  + Volume of the sphere = 2.36 + 47.71 = 50.07 in³

<pWhen the cylinder and the sphere are expanded by a scale factor of 2, the height (h') of the cylinder becomes 3/2 = 1.5 inches and the radius (r') becomes 0.5/2 = 0.025 inches.

The new volume for the cylinder = πr'²h' = π(0.25)² × 1.5 = 0.29 in³

For the sphere, the new radius is R' = 2.25 / 2 = 1.125 in.

The new volume of the sphere = 4/3 (πR'³) = 4/3 × π × 1.125³ = 5.96 in³

Thus, the new volume of the flask = The new volume of the cylinder  + The new volume of the sphere = 0.29 + 5.96 = 6.25 in³

<pThe ratio of the new volume to the original volume = New Volume of the flask / Volume of the flask = 6.25 / 50.07 = 1/8 = 0.125<pThe resulting volume will thus be 0.125 times the original volume

6 0
4 days ago
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zzz [4022]

Answer:

The solution to the equation is 40

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Step-by-step explanation:

To find the zero of the function, we set the dependent variable (here, m) to zero.

So we have;

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1.25w = 50

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What implication does this have in this context?

Essentially, it means that the couple can send out invitations to a total of 40 people based on their budget.

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Leona [4166]

Answer:

The mean decreases, while the median stays unchanged.

Step-by-step explanation:

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In this scenario, the median maintains its value at $9.5 per hour. The median is represented by the middle line in the box, which remains constant.

Conversely, the range of this data set shrinks from 7 to 3.

Moreover, the mean must decrease because values greater than $11 are no longer represented in the second box plot. The mean is a measure sensitive to such alterations.

Conclusively, the correct finding is The mean decreases, while the median remains unchanged.

8 0
6 days ago
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