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13 days ago

The width of a rectangle is 61 centimeters more than the length. The perimeter is 406 centimeters. Find the length and the width

Mathematics

1 answer:

lawyer [12.5K]13 days ago

5 0

$Step \; 1: \; Assign \; Variables \; for \; the \; unknown \; that \; we \; need \; to \; find$

$Let \; x \; be \; length \; of \; the \; rectangle$

$Step \; 2: \; Set \; up \; equation \; based \; on \; information \;\\ given \; about \; the \; rectangle$

$Statement \; 1: Width \; of \; a \; rectangle \; \\is \; 61cm \; more \; than \; the \; length\\\\Width \; = \; 61+x\\\\Statement \; 2: \; The \; perimeter \; is \; 406cm\\\\Perimeter=2(Length+Width)\\Perimeter =2(x+61+x)\\\\So \; the \; mathematical \; equation \; would \; be \\ 2(x+61+x)=406$

$Step \; 3: \; Solve \; the \; equation \; by \\ undoing \; whatever \; is \; done \; x.\\\\2(x+61+x)=406\\Group \; and \; Combine \; like \; terms \; inside \; the \; parenthesis\\\\2(2x+61)=406\\Distribute \; 2 \; in \; the \; left \; side \; of \; the \; equation\\\\4x+122=406\\Subtract \; 122 \; on \; both \; sides\\\\4x+122-122=406-122\\Simplify \; on \; both \; sides\\\\4x=284\\Divide \; on \; both \; sides\\\\\frac{4x}{4}=\frac{284}{4}\\Simplify \; fractions \; on \; both \; sides\\\\x=71$

$Conclusion:\\Length=x=71cm\\Substituting \; 71 \; for \; x \; and \; find \; Width \; value.\\Width=61+x=71+61=132cm\\\\Length \; is \; 71 cm \; and \; Width \; is 132cm$

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