Machines at a bottling plant are set to fill bottles to 12 ounces. The quality control officer at the plant periodically tests t
he machines to be sure that the bottles are filled to an appropriate amount. The null hypothesis of the test is that the mean is at least 12 ounces. The alternative hypothesis is that the mean is less than 12 ounces. What are the possible types of errors that could be made from this test?
1 answer:
Answer:
In response to the question:
Bottling machinery is calibrated to dispense 12 ounces into each bottle. The quality control personnel routinely checks the machines to ensure the correct volume is filled. The null hypothesis asserts that the average volume meets or exceeds 12 ounces, while the alternative hypothesis posits that it is below this level. What errors could potentially occur in this testing process?
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Explanation:
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Answer:
Part A:
Required workers=20.833≅21
Part B:
Each worker's productivity=2.0833 parts/hour
Part C:
Multifactor productivity=0.0832 Parts/$
Explanation:
Part A:
Total parts produced =100,000
Workers required= Total parts/(Parts per hour* hours per shift*Total Shifts)
Workers required=20.833≅21
Part B:
Individual worker productivity:
Part C:
Total material costs= $10*100,000=$1,000,000
Capital cost= $100,000
Total labor expenses=
Total labor expenses=$100,800
Multifactor productivity=Total Parts/(Total material costs+capital costs+Total labor expenses)
Answer:
additional revenue = $26,250
relevant costs:
direct materials = 350 x $82 = $28,700
direct labor = 525 x $15 = $7,875
setup hours = 1 x $5 = $5
inspection costs = 20 x $5 = $100
machining = 175 x $3 = $525
total relevant costs = $37,205
1) change in income if order is accepted:
total revenue - total relevant costs = $26,250 - $37,205 = -$10,955
the company will incur a loss of $10,955 if the order is approved.
2) if the cost of direct materials is decreased by $13 per unit = $13 x 350 = $4,550, and if direct labor can be reduced by 0.5 hours per unit = 175 hours (= 175 x $15 = $2,625) ⇒ total relevant costs will be lowered by $7,175.
It results in a $3,780 (= $10,955 - $7,175) loss if the special order is accepted.
Answer:
Part a:
Show the probability density function for the waiting times at Kroger, assuming they are exponentially distributed.
Solution:
Probability density function f(x) = (1/ )*e-x/ = (1/26)*e-x/26 (result)
Part b:
Calculate the probability that a customer waits between 15 and 30 seconds.
Solution:
0.2462
Part c:
Determine the probability that a customer must wait longer than 2 minutes.
Solution:
0.0099
Explanation:
All calculations are included.
