answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jobisdone
15 days ago
7

A spaceship moves at a speed of 0.95 c away from the Earth. It shoots a star wars torpedo toward the Earthat a speed of 0.90 c r

elative to the ship. What is the velocity of the torpedo relative to the Earth? (The direction in which the spaceship move
Physics
1 answer:
Sav [3.1K]15 days ago
5 0

Answer:

0.345 c

Explanation:

v_{se} = speed of spaceship with respect to earth = 0.95 c

v_{ts} = speed of torpedo with respect to spaceship = - 0.90 c

v_{te} = speed of torpedo with respect to earth

The velocity of the torpedo in relation to earth is calculated as

v_{te}=\frac{v_{se} + v_{ts}}{1 + \frac{v_{se}v_{ts}}{c^{2}}}

v_{te}=\frac{0.95c + (- 0.90 c)}{1 + \frac{(0.95 c)(- 0.90 c))}{c^{2}}}

v_{te} = 0.345 c

You might be interested in
When the displacement of a mass on a spring is 1/2a the half of the amplitude, what fraction of the mechanical energy is kinetic
ValentinkaMS [3465]
Total energy associated with a spring:
E = \frac{1}{2} kx^2 + \frac{1}{2} mv^2 = \frac{1}{2} ka^2

When x = 0.5a:
\frac{1}{2} k \frac{a}{2} ^2 + \frac{1}{2} mv^2 = \frac{1}{2} ka^2 \\ \frac{1}{2} mv^2 = \frac{1}{2} ka^2 - \frac{1}{8} ka^2 = \frac{3}{8} ka^2

The ratio:
\frac{ \frac{3}{8}ka^2 }{ \frac{1}{2} ka^2} = \frac{3}{4}
5 0
21 day ago
Read 2 more answers
 A bartender slides a beer mug at 1.50 m/s toward a customer at the end of a frictionless bar that is 1.20 m tall. The customer
serg [3582]

Response:

a) The mug makes contact with the ground 0.7425m from the bar's end. b) |V|=5.08m/s θ= -72.82°

Clarification:

To address this issue, we begin with a diagram depicting the situation. (refer to the attached illustration).

a)

The illustration shows that the problem involves motion in two dimensions. To determine how far from the bar the mug lands, we need to find the time the mug remains airborne by examining its vertical motion.

To compute the time, we utilize the following formula with the known values:

y_{f}=y_{0}+v_{y0}t+\frac{1}{2}at^{2}

We have y_{f}=0 and v_{y0}=0, allowing us to simplify the equation to:

0=y_{0}+\frac{1}{2}at^{2}

Now, we can calculate for t:

-y_{0}=\frac{1}{2}at^{2}

-2y_{0}=at^{2}

\frac{-2y_{0}}{a}=t^{2}

t=\sqrt{\frac{-2y_{0}}{a}}

We know y_{0}=1.20m and a=g=-9.8m/s^{2}

The negative gravity indicates the downward motion of the mug. Hence, we substitute these values into the provided formula:

t=\sqrt{\frac{-2(1.20m)}{(-9.8m/s^{2})}}

Which results in:

t=0.495s

This time helps us evaluate the horizontal distance the mug traverses. Since:

V_{x}=\frac{x}{t}

Solving for x, we have:

x=V_{x}t

Substituting the known values yields:

x=(1.5m/s)(0.495s)

This calculates to:

x=0.7425m

b) With the time determining when the mug strikes the ground established, we can find the final velocity in the vertical direction using the formula:

a=\frac{v_{f}-v_{0}}{t}

The initial vertical velocity being zero simplifies our calculations:

a=\frac{v_{f}}{t}

Thus, we can determine the final velocity:

V_{yf}=at

Given that the acceleration equates to gravity (showing a downward effect), we substitute that alongside the previously found time:

V_{yf}=(-9.8m/s^{2})(0.495s)

This leads to:

V_{yf}=-4.851m/s

Now, we ascertain the velocity components:

V_{xf}=1.5m/s and V_{yf]=-4.851m/s

Next, we find the speed by calculating the vector's magnitude:

|V|=\sqrt{V_{x}^{2}+V_{y}^{2}}

<pThus:

|V|=\sqrt{(1.5m/s)^{2}+(-4.851m/s)^{2}

Yielding:

|V|=5.08m/s

Lastly, to ascertain the impact direction, we apply the equation:

\theta = tan^{-1} (\frac{V_{y}}{V_{x}})

<pFulfilling this provides:

\theta = tan^{-1} (\frac{-4.851m/s}{(1.5m/s)})

<pLeading to:

\theta = -72.82^{o}

4 0
1 month ago
An airplane flies with a velocity of 55.0 m/s [35o N of W] with respect to the air (this is known as air speed). If the velocity
ValentinkaMS [3465]
V - wind speed;
53° - 35° = 18°
v² = 55² + 40² - 2 · 55 · 40 · cos 18°
v² = 3025 + 1600 - 2 · 55 · 40 · 0.951
v² = 440.6
v = √440.6
v = 20.99 ≈ 21 m/s
Conclusion: The wind speed calculates to 21 m/s.  
5 0
22 days ago
What is an example of a renewable resource?
ValentinkaMS [3465]

An example of a renewable resource could be a car, a house, or a phone

6 0
1 month ago
Read 2 more answers
How many times could Haley fly bewteen the two flowers in 1 minute (60 seconds)​
Yuliya22 [3333]
The answer is 30 seconds.
7 0
28 days ago
Read 2 more answers
Other questions:
  • 2) Billy jumps upward with a velocity of 4.2 m/s off a 6m high diving board. What is his final velocity once he hits the water?
    15·1 answer
  • Early investigators (including Thomas Young) measured the thickness of wool fibers using diffraction. One early instrument used
    15·1 answer
  • 1. Si comprimes un globo hasta reducir su volumen a un tercio de su valor original, ¿cuánto aumenta la presión en su interior?
    7·1 answer
  • A segment of wire of total length 2.0 m is formed into a circular loop having 5.0 turns. If the wire carries a 1.2-A current, de
    6·1 answer
  • Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
    6·1 answer
  • A combined circuit has two resistors in series (27.5 ohms and 33.0 ohms) and another in parallel (22.0 ohms). If the power sourc
    15·1 answer
  • A steel projectile is shot horizontally at 20m/s from the top of a 40m tower. How long does it take to hit the ground? How far f
    15·1 answer
  • Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is
    9·1 answer
  • An 8.0-kg history textbook is placed on a 1.25-m high desk. How large is the gravitational potential energy of the textbook-Eart
    11·2 answers
  • The chart shows rate of decay. A 3 column table with 7 rows. The first column is Half-lives elapsed, with entries 0, 1, 2, 3, 4,
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!