Answer:
Color contrast refers to the disparity in brightness between text (or any foreground item) and the background it is set against.
Explanation:
In the realm of web accessibility, the extent to which one color contrasts with another dictates whether the information can be easily read by most individuals.
Contrast creates visual differences and helps elements stand out.
Answer:
The decimal representation of 101₂² from base 2 equals 25 in base 10.
Explanation:
To derive the decimal equivalent of 101₂²;
101₂ × 101₂ results in 101₂ + 0₂ + 10100₂.
In this expression, we observe that the '2' in the hundred's place must be converted to '0' while carrying over '1' to the thousand's position, leading to;
101₂ + 0₂ + 10100₂ = 11001₂.
This shows that;
101₂² = 11001₂.
Next, we convert the outcome of squaring the base 2 number, 11001₂, into base 10 through the following method;
Converting 11001₂ to base 10 results in;
1 × 2⁴ + 1 × 2³ + 0 × 2² + 0 × 2¹ + 1 × 2⁰.
The calculation yields;
16 + 8 + 0 + 0 + 1 = 25₁₀.
Answer:
SyntaxError.
Explanation:
https://www.quora.com/In-Python-what-kind-of-error-is-returned-by-the-following-code-e-g-NameError-ValueError-IOError-etc-def-my_func-n1-n2-return-n1-n2-my_func-1-2-3 original source
brainlest plz
Answer:
Explanation:
public class Team {
private String teamName;
private int teamWins;
private int teamLosses;
public String getTeamName() {
return teamName;
}
public void setTeamName(String teamName) {
this.teamName = teamName;
}
public int getTeamWins() {
return teamWins;
}
public void setTeamWins(int teamWins) {
this.teamWins = teamWins;
}
public int getTeamLosses() {
return teamLosses;
}
public void setTeamLosses(int teamLosses) {
this.teamLosses = teamLosses;
}
public double getWinPercentage() {
return teamWins / (double) (teamWins + teamLosses);
}
}
Response: 1,500,000 bytes.
Clarification:
If we assume the image dimensions are 4000 pixels in width and 3000 pixels in height, the total uncompressed image will consist of 4000*3000= 12,000,000 pixels.
In the case of a binary image, each pixel can have only two values, which necessitates one bit for each pixel.
This indicates that we need to accommodate 12,000,000 bits.
Given that 1 byte equals 8 bits.
So, to store an uncompressed binary image sized 4000 x 3000 pixels, 12,000,000/8 bytes is required ⇒ 1,500,000 bytes.
