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qaws
2 months ago
14

If A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4) form two line segments, and , which condition needs to be met to prove ?

Mathematics
2 answers:
zzz [12.3K]2 months ago
7 0

The correct choice is C

Detailed explanation:

Zina [12.3K]2 months ago
5 0
The answer
the full question is
If A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4) create two line segments, and AB ⊥ CD, what condition must be satisfied to establish that AB ⊥ CD?

Let A(x1, y1) and B(x2, y2) represent the first line, while C(x3, y3) and D(x4, y4) represent the second line.

The slope for the first line is given by m = (y2 - y1) / (x2 - x1).
For the second line, the slope is m' = (y4 - y3) / (x4 - x3).

The necessary condition to demonstrate that AB ⊥ CD is

                           
                    (y2 - y1) * (y4 - y3)
m × m' =  ---------  ×  ------------ = -1
                    (x2 - x1)    (y4 - y3)
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Using the extended Euclidean algorithm, find the multiplicative inverse of a. 1234 mod 4321 b. 24140 mod 40902
AnnZ [12381]

(a) The multiplicative inverse of 1234 (mod 4321) is x so that 1234*x ≡ 1 (mod 4321). We can apply Euclid's algorithm:

4321 = 1234 * 3 + 619

1234 = 619 * 1 + 615

619 = 615 * 1 + 4

615 = 4 * 153 + 3

4 = 3 * 1 + 1

Now we will express 1 as a linear combination of 4321 and 1234:

1 = 4 - 3

1 = 4 - (615 - 4 * 153) = 4 * 154 - 615

1 = 619 * 154 - 155 * (1234 - 619) = 619 * 309 - 155 * 1234

1 = (4321 - 1234 * 3) * 309 - 155 * 1234 = 4321 * 309 - 1082 * 1234

This reduces to

1 ≡ -1082 * 1234 (mod 4321)

Thus, the inverse is

-1082 ≡ 3239 (mod 4321)

(b) Since both 24140 and 40902 are even, their GCD cannot equal 1, indicating no inverse exists.

8 0
2 months ago
You have diving lessons every fifth day and swimming lessons every third day. Today you have both lessons. In how many days will
lawyer [12517]
You will achieve this in 15 days. Both 5 and 3 have a least common multiple of 15.
5 0
2 months ago
A common inhabitant of human intestines is the bacterium Escherichia coli, named after the German pediatrician Theodor Escherich
babunello [11817]
A.) P(t) = P0e^(kt)
P(20/60) = 40 e^(20k/60)
80 = 40 e^(k/3)
e^(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)

b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells

d.) Rate of change = e^(8k) = e^(8(3ln(2))) = e^(24ln(2)) = e^(16.6355) = 16777216 cells/hour

e.) P(t) = 40(2)^(3t); t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
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8 0
2 months ago
Read 2 more answers
A bicyclist travels 1 mile in 5 minutes. If m represents minutes, what does the expression m over 5 represent
tester [12383]
The expression m over 5 indicates the miles traveled by the cyclist in a span of 5 minutes. This represents a value corresponding to speed. It describes the magnitude of velocity, reflecting the total distance covered within a specific time frame. As it lacks direction, it is classified as a scalar quantity. The dimensions include distance per time with SI units being meters per second. Alternative measurements can include kilometers per hour and miles per hour. In contrast, the vector equivalent known as velocity incorporates both speed and direction, signified through positive and negative indicators.
4 0
1 month ago
Holly bought 23 tickets to the baseball game. She got a group rate that gave her $4 off of the regular ticket price for each tic
Leona [12618]

Answer:

The standard ticket price was $12.

Step-by-step explanation:

Let’s denote P the normal ticket price, which would total

23P if she had purchased tickets for that amount.

However, since Holly received a $4 discount on each ticket, her cost for one ticket became

P-4

and with 23 tickets, her total cost was

23(P-4)

amounting to $184; thus, we conclude

23(P-4)=184

we will solve this equation as follows:

23(P-4)=184

23P-4(23)=184

23P-92=184

23P=276

\boxed{ P=12}

Therefore, the regular price amounted to $12.

5 0
1 month ago
Read 2 more answers
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