Tickets to a play are $12.00 for adults. Children receive a discount and only have to pay $8.00. If 40 people attend the play an

Respuesta:

Explicación paso a paso:

V=1/2lbh

V=1/2×15×8×6

V=360pulgadas

9. Observing the pattern, the decimal digit at position n is 9 when n is even and 0 when n is odd. Because 44 is an even number, the 44th digit after the decimal point is 9.

Answer:

(1) The necessary proportion of spirit to varnish stands at 1:3.

(2) A total of 80 ml of mineral spirit is required.

(3) The ratio of the heights to the widths of the tapestries is 3:2.

Step-by-step explanation:

(1) To achieve a mixture containing 25% mineral spirit, the blend consists of 25% spirit and 75% varnish.

Therefore,

Consequently, the proportion of spirit to varnish is 1:3.

(2) Using 240ml of varnish indicates this is 75% of the entire solution, which means the ratio of varnish to the total solution is 3:4.

Let the total solution quantity be .

Thus, .

⇒

⇒

⇒

⇒

This means the total solution amounts to 320 ml.

Now, calculating Spirit = Total solution - Varnish

⇒Spirit = 320ml-240ml

⇒Spirit = 80ml

Therefore, when using 240 ml of varnish, you will require 80 ml of mineral spirit.

(3) The dimensions of Robison's tapestries are uniform at 1.5m in length and 1m in width. Initially, to obtain whole numbers, we multiply these dimensions by 10.

Thus, the dimensions become 15m long and 10m wide.

Now, the proportion of Height to Width is 15:10

⇒

⇒

Thus, the proportion of the heights of the tapestries to their widths is 3:2.

Sample Answer: To determine the difference between 10 and 13, you apply the concept of additive inverses. Juan is lacking $3 to buy his supplies.

Answer:

The mean and center will be nearly identical, while the variability in simulation B will exceed that of simulation A.

Step-by-step explanation:

Solution

In general, the size of the sample significantly influences the distribution.

As a guideline, by quadrupling the sample size, the sampling error typically reduces by half.

Here, simulation B has a sample size that is twice that of simulation A.

Thus, the sampling error related to the mean is affected, and it stands that A does not have a greater value.

However, its sample size is considerable for this context, making them nearly equal.

Additionally, increased trials lead to decreased variability in simulation. A displays lesser variability.

As trial numbers increase, variability in simulation declines, hence A has lesser variability.