Answer:
Option 1 is valid, which entails 2 hours of walking and 12 hours of running.
Step-by-step explanation:
The equations provided are:
3w + 6r ≥ 36
3w + 6r ≤ 90
We'll assess which options comply with these equations.
1) 2 hours walking; 12 hours running
w = 2 and r = 12
3w + 6r ≥ 36
3(2) + 6(12) ≥ 36
6+72 ≥ 36
78 ≥ 36
3w + 6r ≤ 90
3(2) + 6(12) ≤ 90
6+72 ≤ 90
78 ≤ 90
Both equations are satisfied. Option 1 is valid.
2) 4 hours walking; 3 hours running
w = 4 and r = 3
3w + 6r ≥ 36
3(4) + 6(3) ≥ 36
12+18 ≥ 36
30 ≥ 36 (this does not hold since 30 < 36)
3w + 6r ≤ 90
3(4) + 6(3) ≤ 90
12+18 ≤ 90
30 ≤ 90
Thus, Option 2 is invalid.
3) 9 hours running; 12 hours walking
w = 9 and r = 12
3w + 6r ≥ 36
3(9) + 6(12) ≥ 36
27+72 ≥ 36
99 ≥ 36
3w + 6r ≤ 90
3(9) + 6(12) ≤ 90
27+72 ≤ 90
99 ≤ 90 (this does not hold since 99 > 90)
Option 3 is invalid.
4) 12 hours walking; 10 hours running
w = 12 and r = 10
3w + 6r ≥ 36
3(12) + 6(10) ≥ 36
36+60 ≥ 36
96 ≥ 36
3w + 6r ≤ 90
3(12) + 6(10) ≤ 90
36 + 60 ≤ 90
96 ≤ 90 (this does not hold since 96 > 90)
So, Option 4 is invalid.
Initially, we need to determine how fast he skis in a minute without considering any speed increase.
To do that, we'll divide the total distance by the time.
960 divided by 5 equals 192.
Therefore, his speed is 192 meters per second.
Now, let's add 20 to this figure.
192 plus 20 equals 212.
Now, to calculate how far he can travel in 10 minutes, we multiply 212 by 10.
212 times 10 equals 2120.
Thus, Alex can cover 2120 meters in 10 minutes.
A geometric sequence models the bounce heights:
Use the formula
A (subscript n) = Ar(n-1)
a = the first-term value
n = the index of the term you want (for the fourth peak, n = 4)
r = common ratio, found by dividing the second term by the first
Here r = 18/27 = 2/3 because 27×(2/3) = 18, and similarly 18×(2/3) = 12
For the fourth peak n = 4
Compute: 4th term = 27(2/3)^(4-1) = 8
Therefore the height at the fourth peak is 8
