the matrix P that you need is P=(1/

) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]]Step-by-step breakdown:1º) Identify the eigenvalues of the matrix in a specific sequence.2º) Determine the eigenvectors corresponding to each eigenvalue.Helpful Note: The matrix A can be expressed as A =

D P3º) The matrix D is diagonal and contains the eigenvalues arranged in order.4º) The matrix P should consist of the normalized eigenvectors listed in the correct sequence (as columns).Another Note: Keep in mind that

·P = I; therefore, if A =

D P, then:P A

= P

D P

= I D I = DThus, the P we seek is generated from the diagonalization process.Important Advice: Here, A is a block matrix with zero non-diagonal submatrices, which allows us to derive the eigenvalues using the diagonal submatrices alone. This reduces the problem to calculating the eigenvalues of A₁₁ = A ₂₂ = [[5 3],[3 5]]Working through the solution:1º) The eigenvalues of A₁₁ are {8,2}, hence the D matrix is
![\left[\begin{array}{cccc}8&0&0&0\\0&2&0&0\\0&0&8&0\\0&0&0&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D8%260%260%260%5C%5C0%262%260%260%5C%5C0%260%268%260%5C%5C0%260%260%262%5Cend%7Barray%7D%5Cright%5D)
2º) The eigenvectors of A₁₁ are P₈= {[1 1]T} P₂= {[1 -1]T}, leading to normalized eigenvectors expressed as P = (1/
) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]] (you can observe that P =
in this instance).In reference to "tip 2": P A
= P
D P
= I D I = DTherefore, the P obtained is indeed what you need.