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Mazyrski
2 days ago
14

Find a matrix P such that PTAP orthogonally diagonalizes A. Verify that PTAP gives the proper diagonal form. (Enter each matrix

in the form [[row 1], [row 2], ...], where each row is a comma-separated list.) A = 5 3 0 0 3 5 0 0 0 0 5 3 0 0 3 5
Mathematics
1 answer:
Zina [12K]2 days ago
4 0
the matrix P that you need is P=(1/\sqrt{2}) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]]Step-by-step breakdown:1º) Identify the eigenvalues of the matrix in a specific sequence.2º) Determine the eigenvectors corresponding to each eigenvalue.Helpful Note: The matrix A can be expressed as A = P^{t} D P3º) The matrix D is diagonal and contains the eigenvalues arranged in order.4º) The matrix P should consist of the normalized eigenvectors listed in the correct sequence (as columns).Another Note: Keep in mind that P^{t}·P = I; therefore, if A = P^{t} D P, then:P A P^{t} = P  P^{t} D P P^{t} = I D I = DThus, the P we seek is generated from the diagonalization process.Important Advice: Here, A is a block matrix with zero non-diagonal submatrices, which allows us to derive the eigenvalues using the diagonal submatrices alone. This reduces the problem to calculating the eigenvalues of A₁₁ = A ₂₂ = [[5 3],[3 5]]Working through the solution:1º) The eigenvalues of A₁₁ are {8,2}, hence the D matrix is \left[\begin{array}{cccc}8&0&0&0\\0&2&0&0\\0&0&8&0\\0&0&0&2\end{array}\right]

2º) The eigenvectors of A₁₁ are P₈= {[1 1]T} P₂= {[1 -1]T}, leading to normalized eigenvectors expressed as P = (1/\sqrt{2}) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]] (you can observe that P =  P^{t} in this instance).In reference to "tip 2": P A P^{t} = P  P^{t} D P P^{t} = I D I = DTherefore, the P obtained is indeed what you need.

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Effective interest rate = Daily interest rate = Annual interest rate/number of days per year

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9 days ago
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Respuesta:

Un total de 1242 estudiantes de sexto grado participaron en la excursión.

Explicación paso a paso:

A partir de los datos proporcionados, se sabe que el teatro tiene 2760 asientos y que los estudiantes ocuparon el 45% de ellos, por lo que para encontrar cuántos estudiantes de sexto grado asistieron a la excursión, hay que calcular el 45% de 2760:

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Así que, de acuerdo a esto, la respuesta es que 1242 estudiantes de sexto grado estuvieron en la excursión.

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24 days ago
Estimate the sum of 196 and 482
Svet_ta [12361]

we understand that

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case a) We round to the nearest hundred

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case b) We round to the nearest ten

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Answer:

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Step-by-step explanation:

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17 days ago
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