As a part-time contractor, you want to test a new cement mixture for a project. You need 2 34 wheelbarrows of sand to make 8 whe

Given that,

Julia completes a 20-mile bike ride in 1.2 hours.

The distance Julia covers is 20 miles and her time taken is 1.2 hours.

Therefore, Julia's speed = = 16.67 mph

Katie finishes the same 20-mile ride in 1.6 hours.

Katie’s distance is 20 miles and her time is 1.6 hours.

Hence, Katie's speed = = 12.5 mph

To determine how much faster Julia rides compared to Katie, subtract Katie’s speed from Julia’s speed.

Thus, 16.67 mph minus 12.5 mph equals 4.17 mph, approximately 4.2 mph.

Consequently, Julia cycles 4.2 mph faster than Katie.

Given the specified angles, one is 90 degrees, indicating that the triangle is a right triangle. With provided angles and one side representing the hypotenuse (the longest side), the area is determined using the formula: Area = 1/2 * base * height. Let's compute the height and base:

From sin 75, we derive height = 1.67.
And from cos 75, we obtain base = 0.45.

Calculating area gives us Area = (0.45 * 1.67) / 2, resulting in 0.37 square units.

Thus, the triangle's area is approximately 0.37 square units.

V = x³ - 6x²y + 12xy² - 8y³

V = (x - 2y)³

   = (x - 2y)(x - 2y)(x - 2y) ( start by expanding the first pair of factors )

   = (x² - 4xy + 4y²)(x - 2y) ( multiply the terms from the first group with those in the second )

   = x³ - 4x²y + 4xy² - 2x²y + 8xy² - 8y³ ( combine similar terms )

  = x³ - 6x²y + 12xy² - 8y³

Answer:

Ants weigh approximately 118,615,000mg more.

Step-by-step explanation:

Based on a quick search, the average housefly weighs around 11.5mg, while an ant averages at 3.5mg. With these average weights, we can calculate the total weight of each species.

Flies: 3,990,000 * 11.5mg = 45,885,000mg

Ants: 47,000,000 * 3.5mg = 164,500,000mg

Consequently, it's clear that the 47 million ants possess a greater mass, specifically

164,500,000 - 45,885,000 = 118,615,000mg more

Part A:

The probability that all three strangers have their birthdays on a Wednesday is calculated as





Part B:

The probability that the birthdays of the three individuals fall on distinct days throughout the week is calculated as





Part C:

The probability that none of the three have their birthdays on a Saturday is determined by