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Svetach
7 days ago
8

As a part-time contractor, you want to test a new cement mixture for a project. You need 2 34 wheelbarrows of sand to make 8 whe

elbarrows of concrete. How much sand will you need to make 248 cubic feet of concrete?
Mathematics
2 answers:
zzz [4K]7 days ago
7 0

Answer: He will require 10.07 cubic feet of sand for the wheelbarrows.

Step-by-step explanation:

Given that

the ratio of wheelbarrows filled with sand to those filled with concrete is expressed as

2\dfrac{3}{4}:8\\\\=\dfrac{11}{4}:8\\\\=11:32

The volume of concrete in wheelbarrows is 248 cubic feet.

Then the volume of sand in wheelbarrows can be found as

(\dfrac{11}{32})^3=\dfrac{x}{248}\\\\\dfrac{1331\times 248}{32^3}=x\\\\10.07=x

Therefore, he will require 10.07 cubic feet of sand for the wheelbarrows.

Svet_ta [4.3K]7 days ago
6 0

Response: 85 1/4 cubic feet

Detailed breakdown:

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g European roulette. The game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green. A bal
Leona [4187]

Answer:

The total expected value and standard deviation of your winnings are -$0.081 and $3, respectively.

Step-by-step explanation:

In European roulette, a wheel with 37 slots is spun: 18 are red, 18 are black, and 1 is green.

Bettors can wager on either red or black. Winning on their chosen color means they double their bet, while losing means they forfeit their stake.

Define the probability for the ball landing in a red slot = \frac{18}{37}

The probability of it landing in a black slot = \frac{18}{37}

The probability for landing in the green slot = \frac{1}{37}

Since bets are only placed on red or black,

The winning probability = \frac{18}{37}

and losing probability = \frac{18}{37}+\frac{1}{37}

= \frac{19}{37}

If a gambler wins, they receive $3, and if they lose, it amounts to -$3.

The expected value of the total winnings is hence;

E(X) = \sum X \times P(X)

= \$3 \times \frac{18}{37} + (-\$3 \times \frac{19}{37})

= \$3 \times (-\frac{1}{37})  = -$0.081

Furthermore, the standard deviation of the total winnings is given by;

S.D.(X) = \sqrt{(\sum X^{2} \times P(X))-(\sum X \times P(X))^{2} }

<pTherefore, E(X^{2})=\sum X^{2} \times P(X)

= \$3^{2} \times \frac{18}{37} + (-\$3^{2} \times \frac{19}{37})

= \$9 \times (\frac{18}{37}+\frac{19}{37})  = $9

Thus, S.D.(X) = \sqrt{\$9-(-\$0.081)^{2} }

= \sqrt{8.993}  = $2.99 ≈ $3

Consequently, the anticipated value and standard deviation of your total winnings are -$0.081 and $3, respectively.

6 0
9 days ago
The measure of central angle QRS is StartFraction 8 pi Over 9 EndFraction radians. What is the area of the shaded sector? 36Pi u
babunello [3666]

The illustration is omitted. Please see the attachment below.

Answer:

The area of the shaded sector is 144π square units.

Step-by-step breakdown:

Given:

The central angle for the sector is, \theta=\frac{8\pi}{9}\ rad

The circle's radius is, R=18\ units

The area of a sector with radius 'R' and angle \theta can be determined with:

A=\frac{1}{2}R^2\theta

Substituting \theta=\frac{8\pi}{9},R=18 gives

A=\frac{1}{2}\times (18)^2\times \frac{8\pi}{9}\\\\A=(\frac{324\times 4}{9})\pi\\\\A=(36\times 4)\pi\\\\A=144\pi\ units^2

Thus, the area of the shaded sector calculates to 144π square units.

5 0
11 days ago
Read 2 more answers
Suppose that a student is randomly selected from a large high school. The probability that the student is a senior is 0.22. The
lawyer [4039]

Answer: La probabilidad que necesitamos es 0.16.

Step-by-step explanation:

Se nos proporciona que

La probabilidad de que el estudiante sea un senior = 0.22

La probabilidad de que el estudiante tenga una licencia de conducir = 0.30

La probabilidad de que el estudiante sea un senior o tenga una licencia de conducir = 0.36

Buscamos la probabilidad de que el estudiante sea un senior y tenga licencia de conducir.

Según la pregunta,

P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\\P(S\cap D)=0.22+0.30-0.36\\\\P(S\cap D)=0.16

Por lo tanto, la probabilidad que necesitamos es 0.16.

3 0
5 days ago
Eight identical slips of paper, each containing one number from one to eight, inclusive, are mixed up inside a bag. Subset A of
PIT_PIT [3949]

Answer: The correct choice is (C) A = {1, 2, 3, 4, 5, 7, 8}.

Step-by-step explanation: We have eight identical slips of paper, each numbered from one to eight, which have been mixed inside a bag.

The sample space, S is as follows:

S = {1, 2, 3, 4, 5, 6, 7, 8}.

Subset A consists of the complement of the event where the number 6 is drawn.

Let 'B' denote the event of drawing the number 6.

Thus, B = {6}.

Since 'A' represents the complement of 'B', it will include all elements in the sample space 'S' that are not part of set 'B'.

Therefore,

A = B' = {1, 2, 3, 4, 5, 7, 8}

So, A = {1, 2, 3, 4, 5, 7, 8}.

Consequently, (C) is the correct choice.

7 0
23 hours ago
Read 2 more answers
Match each step to its justification to solve 2x+5=19
Inessa [3926]
It includes the procedures to reach that specific point.
Some of them are arranged incorrectly.
I will label them with letters.

The sequence is:
A: 2x+5=19
B: 2x+5-5=19-5
C: 2x=14
D: 2x/2=14/2
E: x=7


A: initial condition
B: we subtracted 5 from both sides based on the subtraction property of equality
C: perform the subtraction
D: applying the division property of equality (dividing both sides by 2)
E: result of the division
5 0
7 days ago
Read 2 more answers
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