Answer:
Step-by-step breakdown:
You may consider a structure like the following while keeping in mind your specific notation.
1. | ~( (~Q ->~R) v (R & ~Q) ) Assume
2. | | ~(~Q ->~R) Assume
3. | | | ~(R & ~Q) Assume
4. | | | ~R v Q 3, De Morgan
5. | | | ~Q -> ~R 4 Material implication
6. | | | # 2, 5 Results in a contradiction
7. | | R & ~Q 3-6 indirect proof outcome
8. | ~(~Q ->~R) -> (R & ~Q ) 2-7 Discharging the conditional proof
9. | (~Q ->~R) v (R & ~Q) 8 Material implication derived
10 | # 1,9 Results in contradiction
11. (~Q ->~R) v (R & ~Q) 1-10 Completion via indirect proof
Response:
option D
Step-by-step reasoning:
Provided in the prompt is a right-angled triangle FGH.
Base of triangle = 12
Height of triangle = 5
Hypotenuse of triangle = 13
To solve the question, we'll apply trigonometric identities.
cos(F) = adjacent / hypotenuse
cos(F) = height / hypotenuse
cos(F) = 5 / 13
Thus, the cosine ratio for angle F is 5 / 13
He rents the car for d days, but receives two days at no cost, meaning he only needs to pay for d - 2 days.
Each day's rental costs $45, so for d - 2 days, the cost is 45(d - 2). The total expenditure amounts to $315, leading to the equation
45(d - 2) = 315
Now, let's solve for d, the number of days rented.
45(d - 2) = 315
45d - 90 = 315
45d = 405
d = 9
He rented the car for 9 days.
