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Ulleksa
1 month ago
12

Which of the following is true of how the Internet has responded to the increasing number of devices now using the network? a) T

he Internet protocols are changed every year to adapt to the new devices that have been connected to the network b) While the number of devices connected to the Internet has grown, the network itself has not grown c) The protocols of the Internet were designed to scale as new devices are added d) The protocols of the Internet are no longer necessary thanks to the large number of devices now connected to the network
Computers and Technology
2 answers:
Harlamova29_29 [932]1 month ago
8 0

Answer:

A

Explanation:

Every year, internet protocols are adjusted to accommodate the influx of new devices on the network. In the 1990s, traffic primarily utilized a few protocols.  IPv4 managed packet routing, TCP handled those packets to establish connections, SSL (later TLS) secured those connections, DNS resolved hostnames, and HTTP was the main application layer protocol utilized.

For years, there were minimal modifications to the fundamental internet protocols; HTTP saw the addition of some new headers and methods, TLS underwent gradual updates, TCP improved congestion management, and DNS incorporated features like DNSSEC. Over a lengthy period, these protocols remained consistent as seen on the wire — with the exception of IPv6, which is regularly discussed among network operators.

Consequently, network administrators, vendors, and policymakers seeking to understand (and sometimes regulate) the Internet have implemented various practices based on the protocols’ wire ‘footprint’ — whether to troubleshoot issues, enhance service quality, or enforce policies.

Currently, there are considerable changes happening in core internet protocols. Although these updates aim to remain compatible with the wider Internet to ensure adoption, they might disrupt entities that have exploited undocumented features of existing protocols or assumed stability in certain aspects.

oksian1 [797]1 month ago
5 0

Answer:

It is C, as the protocols were designed for scalability alongside new devices.

Explanation:

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Write an if-else statement to describe an integer. Print "Positive even number" if isEven and is Positive are both true. Print "
Harlamova29_29 [932]

Answer:

Below is the explanation for the C code.

Explanation:

#include <stdio.h>

#include <stdbool.h>

int main(void) {

int userNum;

bool isPositive;

bool isEven;

scanf("%d", &userNum);

isPositive = (userNum > 0);

isEven = ((userNum % 2) == 0);

if(isPositive && isEven){

  printf("Positive even number");

}

else if(isPositive &&!isEven){

  printf("Positive number");

}

else{

  printf("Not a positive number");

}

printf("\n");

return 0;

}

6 0
1 month ago
To encourage good grades, Hermosa High School has decided to award each student a bookstore credit that is 10 times the student’
amid [800]

Answer:

// here's the Java code.

import java.util.*;

// definition of the class

class BookstoreCredit

{

/* method that prints a message including the name and grade point */

   public static void fun(String name,double grade)

   {

// multiplying grade by 10

       grade=grade*10;

// display the message

       System.out.println(name+"\'s average grade is $"+grade);

   }

// main method for the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // scanner instance to read input

       Scanner s=new Scanner(System.in);

        // declaring variables

      String s_name;

      double grade;

      System.out.print("Please enter the name:");

      s_name=s.nextLine();

      System.out.print("Please enter the grade point:");

      grade=s.nextDouble();

   }catch(Exception ex){

       return;}

}

}

Explanation:

Define a string variable named s_name and a double variable named grade. Obtain the name and grade from the user, then invoke the fun() method with these parameters, which will multiply the grade by 10 and output a message that includes the student's name along with their average grade.

Output:

Please enter the name:john

Please enter the grade point:3.2

john's average grade is $32.0

7 0
19 days ago
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