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____
1 month ago
5

A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks

giving a holiday. The researcher asks 1,000 random selected students if they would support making the Tuesday before Thanksgiving a holiday. Seven hundred students said that they would support the extra holiday. What is the null and alternative hypothesis?
Mathematics
1 answer:
zzz [12.3K]1 month ago
3 0
The null hypothesis is stated as, {H₀}: p = 0.66, H₀: p = 0.66. The alternative hypothesis can be represented as, {Hₐ}: p > 0.66, Hₐ: p > 0.66. For clarity, let p denote the fraction of students that support making the day before Thanksgiving a holiday. Since we are evaluating two different populations, it is necessary to articulate the alternative hypothesis concerning the difference in their means. The ratio indicating that two-thirds of the students support this holiday is p = 0.66, derived as follows: The null hypothesis is, {H₀}: p = 0.66, H₀: p = 0.66. In contrast, the alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ: p > 0.66.
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Answer:

2.1%

Step-by-step explanation:

The compound interest formula can be expressed as:

A=P(1+I)^n\\\\P-Principal \\A-amount\\i-compound \ interest \ rate

Starting with a Principal amount of $6000 and applying an interest rate of 1.5% for the first two years:

A=P(1+i)^n\\\\A_2=6000(1+0.015)^2\\\\A_2=6181.35

We calculate compound interest A_2 for one year at rate i, resulting in $6311.16:

A=P(1+i)^n, n=1, i=i, P=6181.35, A=6311.16\\\\6311.16=6181.35(1+i)^1\\\\\frac{6311.16}{6181.35}=(1+i)\\\\i=\frac{6311.16}{6181.35}-1\\\\i=0.02100

Thus, the interest rate for the third year is 2.1%

7 0
2 months ago
Read 2 more answers
Lesson 3 homework practice mean absolute deviation
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To calculate the mean absolute deviation of
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18*2.50=45
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