Jules goes on a hike that will last 5 hours total. She brings 12 cups of water. After an hour, she has already drunk 3 cups of w

A) Probability is a measure of how likely an event will happen. Here, we calculate the probability of X as: P(X) = X/N, where X is the successful outcomes, and N is the total outcomes. P(E) = E/N = 1033/2851 = 0.3623 P(R) = R/N = 854/2851 = 0.2995 P(D) = D/N = 964/2851 = 0.3381 B) Events E and D are mutually exclusive since students accepted early can't be deferred to the regular admission pool, hence, intersection P(E ∩ D) is 0. C) The count of early accepted students is 1033, and the overall accepted students are 2375. Thus, the probability is: P = 1033/2375 = 0.4349 D) Reformulating the question: What’s the probability of being accepted if applying for early admission? Given that 18% of deferred students ultimately got accepted, 0.18 × 964 = 174 was admitted later. Thus, the probability of being deferred and then accepted becomes: P(DA) = 174/2831 = 0.0610. The chance of randomly selecting a student early accepted or deferred then accepted is: P(E or DA) = 0.0610 + 0.3623 = 0.4233, applying the addition rule.

Answer:

The average for the sampling distribution of the sample proportion is 0.29

The standard deviation for this sampling distribution is 0.01435

Step-by-step explanation:

The mean of the sampling distribution for the sample proportion equals the actual population proportion, which is p = 0.29 in this scenario.

The standard deviation for the sampling distribution of the sample proportion is computed as follows;

Utilizing the provided values;

p = 0.29

1 - p = 0.71

n = 1000

The standard deviation computes to;

Thus, the standard deviation is 0.01435.