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iris
13 days ago
14

The partial factorization of x2 – x – 12 is modeled with algebra tiles. An algebra tile configuration. 4 tiles are in the Factor

1 spot: 1 is labeled + x, 3 are labeled +. 1 tile is in the Factor 2 spot and is labeled + x. 20 tiles are in the Product spot: 1 is labeled + x squared, 3 are labeled + x, the 4 tiles below + x squared are labeled negative x, and the 12 tiles below the + x tiles are labeled negative. Which unit tiles are needed to complete the factorization? 3 negative unit tiles 3 positive unit tiles 4 negative unit tiles 4 positive unit tiles

Mathematics
2 answers:
Svet_ta [12.7K]13 days ago
8 0

Response:

Stepwise explanation:

Given the expression

x² - x - 12

First, let’s factor this expression

Refer to the attachment for simplification

x² - 4x + 3x - 12

x(x - 4) + 3(x-4)

(x + 3)(x - 4)

Consequently, 4 negative unit tiles are necessary

tester [12.3K]13 days ago
3 0

Response:

A total of 4 negative tiles

Stepwise explanation:

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1 month ago
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A sample prepared for a chemical measurement is completed correctly by 21% of the lab technicians, completed with minor error by
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Answer:

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10 days ago
A high school wants to sell postage stamps with the school logo on them. The fundraising group have purchased 500 sheets of stam
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Response:

a) Expense

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b) Revenue from sales

S(q)=20q\\\\S(500)=20\cdot 500 = 10,000

c) Values table

\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right]

d) Included

e) Breakeven point = 12.5 sheets

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In-depth analysis:

a) There is a fixed cost of $50 for the image.

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C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050

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c) Values table

\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right]

d) Included

e) To avoid losses, the minimum number of sheets that must be sold is determined by the breakeven point (BEP), calculated by equating sales income to costs:

S(q)=C(q)\\\\20q=50+16q\\\\(20-16)q=50\\\\4q=50\\\\q=50/4=12.5

f) Profit is computed as the difference between sales income and the cost:

P(500)=S(500)-C(500)\\\\P(500)=20\cdot 500-(50+16\cdot 500)=10,000-8,050=1,950

3 0
1 month ago
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