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ivanzaharov
13 days ago
14

In baseball, a player pitches a ball from the mound to a catcher behind the plate. A pitch that passes over the plate above the

batter’s knees and below his chest is a strike. All other pitches are “balls,” provided the batter does not swing at them or hit them foul.
The table below breaks a sample number of pitches into strikes and balls over the plate and not over the plate.




Over plate (Event C)


Not over plate (Event D)


Strike (Event A) 10 0

Ball (Event B) 5 20


Which conditional probability below is either inaccurately described or inaccurately calculated?

The probability that a pitch not over the plate is a ball is 1. So, P(B | D) = 1.

The probability that a pitch over the plate is a strike is 10:15. So, ...

The probability that a pitch over the plate is a ball is 5:10. So, P(B | C) = 0.5.

The probability that a pitch not over the plate is a strike is zero. So, P(A | D) = 0.
I have no clue how to do this. Show your work.
Mathematics
2 answers:
tester [12.3K]13 days ago
8 0
The probability that a pitch over the plate is a ball is measured at 5:10, giving P(B | C) = 0.5. A detailed walkthrough would be: P(B | C) = n(B & C)/n(C) = 5/(10+5) = 5/15 which simplifies to 5: 15.
Zina [12.3K]13 days ago
7 0
To resolve this question, simply tally the probabilities of the options. The likelihood of a pitch not crossing the plate being a strike is non-existent; thus, P(A | D) = 0. This is true as it calculates to 0/0+20= 0. The likelihood of a pitch not over the plate being a ball is complete; therefore, P(B | D) = 1. This holds true as it equals 20/20+0= 1. The likelihood of a pitch over the plate being a strike is 10:15. It’s incomplete but seems correct; it can be calculated as 10/10+5= 10/15 = 2/3. The probability for a pitch over the plate labeled a ball is 5:10; therefore, P(B | C) = 0.5.
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The number of pages in the U.S. tax code exceeds the number of pages in the King James Bible by 18,528. The combined number of p
Leona [12618]
Let x represent the number of pages in the U.S. Tax Code and y denote the pages in the King James Bible.

According to the provided information,
x= y+18,528 ⇒ y=x-18,528
x+y = 21,472 ⇒ x+(x-18,528) = 21,472 ⇒ x+x-18,528 = 21,472 ⇒ 2x= 18,528+21,472 ⇒ 2x = 40,000 ⇒ x=40,000/2 = 20,000 pages

Therefore, the U.S. tax code consists of 20,000 pages.
6 0
1 month ago
Read 2 more answers
What is the answer? The glee club has 120 cupcakes to sell. they have decided to arrange the cupcakes in the shape of a rectangl
PIT_PIT [12445]
<span>Determine the configuration of columns and rows for the rectangular arrangement of 120 cupcakes.
=> There must be an even number of rows and an odd number of columns.
=> 120 = 2 x 2 x 2 x 15
=> 120 = 8 x 15
=> 120 = 120
Consequently, the glee club should organize the cupcakes in 8 rows and 15 columns.
This totals up to 120 cupcakes altogether.

</span>



8 0
1 month ago
A frog is sitting exactly in the middle of a board that is five feet long. Every ten seconds he jumps one foot to the left or on
PIT_PIT [12445]

Answer:

Given that the frog jumps every 10 seconds

   (using digits from a random number table)

  • It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
  • Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
  • Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.

Step-by-step explanation:

A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.

Every 10 seconds, the frog jumps left or right.

If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.

If it jumps as LLRLL, it will jump off the board after fifty seconds.

Given that the frog jumps every 10 seconds

   (using digits from a random number table)

  • It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
  • Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
  • Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
4 0
1 month ago
The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
PIT_PIT [12445]

Answer:

The tangent plane equation for the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

We have

The ellipsoid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation for the tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  (Given)

The hyperboloid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The tangent plane equation at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The tangent plane equation for the hyperboloid is

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The tangent plane equation

2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2

Hence, the required tangent plane equation for the hyperboloid is

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

7 0
2 months ago
Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy
Leona [12618]

Answer:

Hello! Your question appears to be missing details; here is the complete version

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

Step-by-step explanation:

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

This provides a comprehensive solution below

4 0
1 month ago
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