c) Step-by-step breakdown: The collision rate is 1.2 incidents per 4 months, which can be expressed as 0.3 incidents monthly. Therefore, the Poisson distribution for the variable X representing monthly collisions is defined as P(X = x) =... for x ∈ N ∪ {0} = 0 otherwise. (1) Where X = 0 denotes no collisions during a 4-month timeframe, substituting gives P(X = 0) =... (2). For a 4-month period, P(No collision in 4 month period) =... (3). Two collisions in a 2-month span translate to 1 per month, thus P(X =1) =... (4). Over 2 months, P(2 collisions in a 2 month period) =... (5). One collision over a 6-month period equates to P(1 collision in 6 months period) =... (6). Consequently, P(1 collision in 6 month period) results in... (7). For no collisions in a 6-month period, P(No collision in 6 months period) =... (8). Finally, the probability of 1 or fewer collisions over six months is P(1 or fewer collision in 6 months period) = (8) + (7) = 0.0785 + 0.1653.
Answer:
91
Step-by-step explanation:
40/.44
<span>As the restaurant owner,
The likelihood of hiring Jun is 0.7 => p(J)
The likelihood of hiring Deron stands at 0.4 => p(D)
The chance of hiring at least one of them is 0.9 => p(J or D)
We can formulate the probability equation:
p(J or D) = p(J) + p(D) - p(J and D) => 0.9 = 0.7 + 0.4 - p(J and D)
p(J and D) = 1.1 - 0.9 = 0.2
Thus, the probability that both Jun and Deron are hired is 0.2.</span>
The equivalence exists because tenths represent one-tenth of a whole. Having 20 tenths means multiplying 20 by 1/10, resulting in 20/10, which simplifies to 2 wholes. Conversely, expressing 2 as 20 tenths yields the same amount.
Four statements:
1) Start by dividing the x-axis into equal segments.
2) n = 212/5 = 42.4.
3) Each segment along the x-axis represents 42.4. This means you can plot the point -212 at x = -5
4) The y-axis can keep its magnitude and you can plot the coordinate of -4 at y = -4
