<span>0.002 1/10 of what
=> (1/10)a = 0.002
=> Multiply both sides by 10 to solve for the unknown number, since we need the value whose one-tenth is 0.002.
=> 10 x (1/10)a = 10 x 0.002
=> a = 0.02
Therefore, 0.002 is one-tenth of 0.02.
To verify, divide 0.02 by 10.
=> 0.02 / 10
=> 0.002
Hence, the solution is confirmed.
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Answer:
50 Educators
Step-by-step explanation:
To tackle this question, the initial step is to calculate the amount of teachers prior to the addition of new staff. For this, I devised Model 1. In this model, teachers are positioned at the top of the ratio and students at the bottom. The variable X represents the number of teachers we are determining. Utilizing this model, I computed 2,100 multiplied by 1 (2,100) and then divided by 14 to conclude there were 150 teachers. Next, I formed a similar model with the updated student-teacher ratio (Model 2). This time, I multiplied 2,100 by 2 (which is 4,200) and divided by 21 to ascertain there are 200 teachers. Having established both the initial and the increased counts of educators, subtracting the original from the new gives you the tally of new teachers, which results in an increase of 50 teachers.
Answer:
CrO₃.
Step-by-step explanation:
First, we will find the chromium percentage in the oxide by using the following process:
Oxygen (O) = 48%
Chromium (Cr) =?
The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:
Cr = 100 – percentage of oxygen
Cr = 100 – 48
Cr = 52%
Next, we will determine the empirical formula for the oxide:
Chromium (Cr) = 52%
Oxygen (O) = 48%
Now, we divide by their molar mass:
Cr = 52/52 = 1
O = 48/16 = 3
Now, divide by the lowest value:
Cr = 1/1 = 1
O = 3/1 = 3
Thus, the empirical formula for the oxide is CrO₃.
Let the number be x. The equation x/5 - 17 = 48 leads to (x - 85)/5 = 48. Multiplying gives x - 85 = 240, so x = 240 + 85, resulting in x = 325.
It exhibits a zero slope.
In the case of a horizontal line, the slope remains constant at 0 since there is no variation.