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Ilia_Sergeevich
7 days ago
11

An inspector inspects large truckloads of potatoes to determine the proportion p in the shipment with major defects prior to usi

ng the potatoes to make potato chips. Unless there is clear evidence that this proportion, p, is less than 0.10, he will reject the shipment. He will test the hypotheses
H0: p = 0.10, Ha: p < 0.10.

e selects an SRS of 100 potatoes from the over 2000 potatoes on the truck. Suppose that six of the potatoes sampled are found to have major defects.
Reference: Ref 18-6

The P-value of this test is
A. 0.4082.
B. 0.0912.
C. 0.0400.
D. less than 0.0002.

A 95% confidence interval for the true proportion of potatoes in the truck that have major defects is
A. 0.034 to 0.086.
B. 0.013 to 0.107.
C. 0.051 to 0.103.
D. 0.026 to 0.128.

Which of the following is true?
A. The inspector will decide to reject the shipment because there's weak evidence that the proportion of potatoes with serious defects is less than 0.10.
B. The inspector might reach the wrong conclusion about the lot of potatoes, whether he returns the shipment or not.
C. Strictly speaking, the inspector should take a larger sample in order to more safely apply the large sample significance test for proportion.
D. All of the above.
Mathematics
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Find the value of $x$ that maximizes $$f(x) = \log (-20x + 12\sqrt{x}).$$ If there is no maximum value, write "NONE".
zzz [12365]
The function can be expressed as:
f(x) = log(-20x + 12√x)
To ascertain the maximum value, differentiate the equation with respect to x and set the derivative to zero. The procedure unfolds as follows.

The differentiation formula is:
d(log u)/dx = du/u ln(10)
Thus,
d/dx = (-20 + 6/√x)/(-20x + 12√x)(ln 10) = 0
-20 + 6/√x = 0
6/√x = 20
From which we derive x = (6/20)² = 9/100

Therefore,
f(x) = log(-20(9/100)+ 12√(9/100)) = 0.2553

The function's maximum value is 0.2553.
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f(n) = -6.5n + 14.5

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