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zvonat
1 month ago
10

A machine in a chocolate factory is set to squirt out a predetermined amount of molten chocolate. When the machine is set to x,

the drop of molten chocolate will be x grams with a standard deviation of 0.01 grams. Suppose you know that nearly all the chocolate chips produced will have a mass within 2 standard deviations of the mean. If you want to minimize the number of chocolate chips that are less than 2 grams, what is the lowest setting of x you should set the machine to
Mathematics
1 answer:
lawyer [12.5K]1 month ago
4 0
I apologize, I need points, but I also require assistance.
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One sphere has a radius of 5.10 cm; another has a radius of 5.00cm. What is the difference in volume (in cubic centimeters) betw
lawyer [12517]
\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\qquad 
\begin{cases}
r=radius\\
-----\\
r_1=5.10\\
r_2=5
\end{cases}\implies \cfrac{V_1}{V_2}\implies \cfrac{\frac{4\pi \cdot 5.10^3}{3}}{\frac{4\pi \cdot 5^3}{3}}
\\\\\\
\cfrac{\underline{4\pi }\cdot 5.10^3}{\underline{3}}\cdot \cfrac{\underline{3}}{\underline{4\pi }\cdot 5^3}\implies \cfrac{5.10^3}{5^3}\implies \cfrac{132.651}{125}
5 0
2 months ago
Read 2 more answers
Doug purchased land for $8,000 in 1995. The year value of the land depreciated by 4% each year thereafter. Use an exponential fu
Leona [12618]

Answer:

Choice C. $6,012

Step-by-step explanation:

We know that

The formula to find the depreciated value is given by

V=P(1-r)^{t}

where

V stands for the depreciated value

P represents the original value

r corresponds to the depreciation rate in decimal

t refers to the Number of Time Periods

In this scenario, we have

t = 7 years

P = $8,000

r = 0.04

Plug these into the formula mentioned earlier

V = 8,000(1-0.04)^{7} = 6,012

Hope this assists you:)

4 0
2 months ago
The figure below shows a partially completed set of steps to construct parallelogram PQRS: Two sides of a parallelogram PQRS are
Inessa [12570]

Response:

∠PQL=∠TRN [Angles corresponding]

Thus, PQ║RS and PQ=RS

Detailed explanation:

The side PQ has been drawn.

A second side QR is traced, forming an acute angle with side PQ.

Now side QR is extended to the left.

Create an arc from point Q such that it intersects QP at M and extends RQ at L. Without altering the compass width (i.e., the distance between the nib and pencil), draw an arc from R to intersect RQ at N. Now measure the distance LM with a compass. Position the compass at N and mark an arc cut from point R. Designate this intersection as T. Draw a line from point R through T. Then measure the length of PQ with the compass. Position your compass at R and create an arc on the produced line RT at S. Thus, we ascertain that PQ║RS and PQ=RS.

This occurs because

∠MQL=∠NRT [corresponding angles, with QR acting as the transversal]

∵PQ║RS  and PQ=RS [This identifies PQRS as a parallelogram]

Out of the four students who illustrated their explanations

Student 2 presented a partially correct but valid explanation.

3 0
1 month ago
The selling price of a box of crackers is $1.75 You mark the crackers up to $2.54 . What is the markup percentage?
Zina [12379]

The markup percentage calculates to 45.14%

Step-by-step explanation:

The given data is:

  • The selling price of a box of crackers is $1.75
  • You increase the price of the crackers to $2.54

Our goal is to find the markup percentage.

Markup percentage = \frac{New-Old}{old} × 100%

Given that the selling price of a box of crackers is $1.75

Thus, Old = 1.75

Since you marked the crackers to $2.54

Thus, New = 2.54

- Substitute the values into the formula

Markup percentage = \frac{2.54-1.75}{1.75} × 100%

Therefore, markup percentage = \frac{0.79}{1.75} × 100%

Therefore, the markup percentage = 0.4514 × 100%

Thus, the markup percentage = 45.14%

The markup percentage equals 45.14%

Learn more:

You can gain additional insights into percentages in

8 0
2 months ago
Read 2 more answers
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