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Bingel
12 days ago
8

Last week, the price of apples at a grocery store was $1.60 per pound. This week, apples at the same grocery store are on sale a

t a 10% discount. What is the total price of 4 1/2 pounds of apples this week at the grocery store? *
Mathematics
2 answers:
tester [3.9K]12 days ago
4 0

Answer:

$6.48

Step-by-step explanation:

Initially calculate the 10% discount on $1.60, which results in $1.44. Then multiply $1.44 by 4.5 to find the total, yielding $6.48.

zzz [4K]12 days ago
3 0

Answer: £6.48

Step-by-step explanation:

1.6 with a 10% discount equals 1.44

Multiplying 1.44 by 4.5 gives

6.48

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Answer:

0.5r

Step-by-step explanation:

If Jerry completed his journey in half the duration that Macy did, it implies Macy's time was twice as lengthy. Assuming Jerry’s speed is r, Macy’s speed would therefore be 0.5r, indicating she travels at half Jerry's pace and takes twice as long to cover the distance.

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3 days ago
6a−3b=5b solve for a:b ratio plz help
babunello [3635]

Add 3b to both sides, then simplify. Next, divide both sides by 6 and simplify it further, leading to the result of a = 4b/3.

8 0
17 hours ago
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Jai Narayan sells two radio sets for 2288 each.
tester [3916]

Answer:

1%

Step-by-step explanation:

The selling price for each radio is $2288.

Total selling price is 2\times 2288=$4576.

Profit is 10%.

Loss is also 10%.

Cost price=\frac{S.P\times 100}{100+gain(in\;percent)}

Cost price=\frac{S.P\times 100}{100-loss(in\;percent)}

Utilizing the formula,

Cost price of the first radio is \frac{2288\times 100}{110}=$2080.

Cost price of the second radio is \frac{2288\times 100}{100-10}=$2542.2.

The combined cost price for both radios totals 2080+2542.2=$4622.2.

Total cost price exceeds total selling price.

Loss equals selling price minus cost price.

Loss is calculated as 4622.2-4576=$46.2.

Loss%=\frac{Loss}{C.P}\times 100

Loss percentage is \frac{46.2}{4622.2}\times 100=1%.

Thus, the loss is 1%.

5 0
3 days ago
Three classes of school children are selling tickets to the school play. the number of tickets sold by these classes, and the nu
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6 0
13 days ago
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What is the empirical formula of an oxide of chromium that is 48 percent oxygen by mass?
Svet_ta [4321]

Answer:

CrO₃.

Step-by-step explanation:

First, we will find the chromium percentage in the oxide by using the following process:

Oxygen (O) = 48%

Chromium (Cr) =?

The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:

Cr = 100 – percentage of oxygen

Cr = 100 – 48

Cr = 52%

Next, we will determine the empirical formula for the oxide:

Chromium (Cr) = 52%

Oxygen (O) = 48%

Now, we divide by their molar mass:

Cr = 52/52 = 1

O = 48/16 = 3

Now, divide by the lowest value:

Cr = 1/1 = 1

O = 3/1 = 3

Thus, the empirical formula for the oxide is CrO₃.

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8 days ago
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