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1 month ago

PLEASE HURRYY I AM BEGGING FOR HELP IVE BEEN STUCK FOR AN HOUR

Mathematics

1 answer:

zzz [12.3K]1 month ago

3 0

Part A:

Please refer to the attached image to view the graph illustrating the inequalities.

There are two distinct lines shown, one with a steeper negative slope than the other. The shaded region in between indicates the solution set.

The green line corresponds to 2x+y≤8, while the blue line represents x+y≥4

Part B:

To determine if (8, 10) is included, substitute x = 8 and y = 10 into both inequalities. If it fails to satisfy either inequality, then it won't be part of the solution area.

2(8) + 10 ≤ 8

16 + 10 ≤ 8

26 ≤ 8... 26 is NOT less than or equal to 8

Hence, (8, 10) cannot be a solution because the inequality does not hold.

Part C:

I will select a random point from the graph, such as (2, 3). For your answer, any point within the shaded region where both x and y are positive would suffice.

The point (2, 3) indicates that Sarah can purchase 2 cupcakes and 3 pieces of fudge, ensuring that she acquires at least 4 pastries for her siblings while adhering to her 8 dollar budget.

Please let me know if you need any further clarification. Happy studying!

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Answer:

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Detailed solution:

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Refer to the provided diagram for clarity.

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x → length in centimeters of each square cutout side

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By substitution:

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Because:

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

Therefore:

Domain is the interval (0,5)

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$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

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3 months ago

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Zina [12379]

Answer:

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Step-by-step explanation:

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To determine this, we will substitute the values of x into each function to see which one accurately produces the corresponding y (f(x)) values provided in the table:

We are presented with four functions, which are:

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3 months ago

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