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Yuki888
1 month ago
6

An instructor at a major research university occasionally teaches summer session and notices that that there are often students

repeating the class. Out of curiosity, she designs a random sample of students enrolled in summer sessions and counts the number repeating a class. She counts 105 students in the sample, of which 19 are repeating the class.She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are:
a) H0:p? =0.181 vs. H?:p=0.1 .
b) H0:p=0.1 vs. H?:p?0.18 .
c) H0:p=0.1 vs. H?:p? =0.181 .
d) H0:p=0.1 vs. H?:p?0.1 .
Mathematics
1 answer:
zzz [12.3K]1 month ago
8 0
We aim to verify the assertion that generally, 10% of students repeat a course, leading us to this hypothesis setup: Null hypothesis: Alternative hypothesis. The most fitting choice for this scenario is: d) H0:p=0.1 vs. H1:p ≠ 0.1. For this case, the provided information includes: the number of students repeating the course, the selected sample size, and the estimated proportion of repeaters. We are testing the claim that generally, 10% of students retake classes, which will be validated through established hypotheses.
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PQ⊥PS , m∠QPR=7x−9, m∠RPS=4x+22<br> Find : m∠QPR
zzz [12365]

Given:

It is stated that

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the measure of ∠QPR.

Formula

According to the problem PR sits between PQ and PS,

Consequently,

∠QPR+∠RPS = 90°

Now,

Inserting the values for ∠RPS and ∠QPR yields

7x-9+4x+22 = 90

or, 11x = 90-22+9

or, 11x = 77

or, x = \frac{77}{11}

or, x = 7

Substituting the value of x = 7 into ∠QPR gives us

∠QPR = 7(7)-9

or, ∠QPR = 40^\circ

So,

The measure of ∠QPR is 40°.

3 0
1 month ago
which equation has an a-value of –2, a b-value of 1, and a c-value of 3? a. 0 = –2x2 x 3 b. 0 = 2x2 x 3 c. 0 = –2x2 3 d. 0 = 2x2
babunello [11817]
To identify the corresponding equation, you can follow these steps:

ax^2 + bx + c = 0
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b = 1
c = 3

-2x^2 + x + 3 = 0

The right result will show as a: 0 = <span>-2x^2 + x + 3.</span>
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1 month ago
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5400000, since the 7 rounds the 8 up to 4.
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2 months ago
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a resorvoir can be filled by an inlet pipe in 24 hours and emptied by an outlet pipe 28 hours. the foreman starts to fill the re
zzz [12365]
To determine the rates at which the inlet and outlet pipes fill and empty the reservoir, we remember that work done equals rate multiplied by time. Let’s denote the inlet rate as i and for the outlet pipe as 0. Therefore,
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In this context, the '1' represents the total number of reservoirs, since the problem states the time needed for each pipe to either fill or empty a singular reservoir. Solving for rates yields:
i = 1/24 reservoirs/hour
o = 1/28 reservoirs/hour

Over the first six hours, the inlet pipe fills (1/24)(6) = 1/4 reservoirs and during the same period, the outlet pipe empties (1/28)(6) = 3/14 reservoirs. To calculate the net volume of the reservoir filled, we subtract the emptying total from the filling total:
1/4 - 3/14 = 1/28 reservoirs (note that if emptying exceeds filling, a negative value results. In such cases, treat that negative value as zero, indicating that the outlet rate surpasses the inlet rate, leading to an empty reservoir).
Now we need to find out how long it will take to fill up one reservoir since we’ve already partially filled 1/28 of it, after closing the outlet pipe. In simpler terms, we need to determine the time required for the inlet pipe to finish filling the remaining 27/28 of the reservoir. Fortunately, we have already established the filling rate for the inlet pipe, leading to the equation:
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4 0
2 months ago
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What is the value of n? 9x27+2x31-28= n
Svet_ta [12734]

n equals 277

9 multiplied by 27 plus 2 multiplied by 31 minus 28 gives n

243 plus 62 minus 28 results in n

305 minus 28 equals n

which means 277 is n


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2 months ago
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