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Yuki888
1 day ago
6

An instructor at a major research university occasionally teaches summer session and notices that that there are often students

repeating the class. Out of curiosity, she designs a random sample of students enrolled in summer sessions and counts the number repeating a class. She counts 105 students in the sample, of which 19 are repeating the class.She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are:
a) H0:p? =0.181 vs. H?:p=0.1 .
b) H0:p=0.1 vs. H?:p?0.18 .
c) H0:p=0.1 vs. H?:p? =0.181 .
d) H0:p=0.1 vs. H?:p?0.1 .
Mathematics
1 answer:
zzz [11.9K]1 day ago
8 0
We aim to verify the assertion that generally, 10% of students repeat a course, leading us to this hypothesis setup: Null hypothesis: Alternative hypothesis. The most fitting choice for this scenario is: d) H0:p=0.1 vs. H1:p ≠ 0.1. For this case, the provided information includes: the number of students repeating the course, the selected sample size, and the estimated proportion of repeaters. We are testing the claim that generally, 10% of students retake classes, which will be validated through established hypotheses.
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In 2010, Rafik bought a house. In 2015, Rafik sold the house to Bianca. He made a 20% profit on the sale. In 2019, Bianca sold t
zzz [11915]

Answer:

£170,000

Step-by-step explanation:

En 2010, Rafik adquirió una casa. Supongamos que el precio de compra fue $x. En 2015, Rafik vendió la casa a Bianca obteniendo un 20% de ganancia. Esto se traduce en 20% de x lo que equivale a 0.2 × x = 0.2x. Por tanto, Rafik vendió la casa a Bianca por x + 0.2x = 1.2x. Bianca compró la casa a 1.2x.

La casa fue vendida por Bianca en 2019 con una pérdida del 5%. Esto implica que el 5% de pérdida equivale a 0.05(1.2x) = 0.06x.

Por consiguiente, la venta de la casa por Bianca se realizó a 1.2x - 0.06x = 1.14x. Dado que la casa se vendió por £193,800.

⇒ 1.14x = 193,800

x = 193,800/1.14

x = £170,000

Rafik pagó £170,000 por la casa en 2010.

7 0
1 month ago
We can calculate EE, the amount of euros that has the same value as DD U.S. dollars, using the equation E=\dfrac{17}{20}DE=
Leona [12193]

Response:

The equation provided is e=\frac{17}{20}d, where e represents euros and d denotes the equivalent value in U.S. Dollars.


We aim to determine the number of euros for 1 U.S. Dollar.


Substituting d=1 in the above equation


results in


e=\frac{17}{20}(1)


Simplifying gives us


e=\frac{17}{20}


By dividing 17 by 20, we get 0.85.


Thus, 0.85 euros are equivalent to 1 U.S. Dollar.


Read more on -

Step-by-step explanation:


5 0
21 day ago
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A solid oblique cone with a slant length of 17 units is placed inside an empty cylinder with a congruent base of radius 8 units
PIT_PIT [11965]

Step 1

Calculate the volume of a cylinder

We understand that

the volume of a cylinder can be expressed as

V1=\pi r^{2} h

In this scenario

r=8\ units \\ h=15\ units

Insert the values

V1=\pi 8^{2} 15

V1=960\pi\ units^{3}

Step 2

Calculate the volume of a cone

We are aware that

the volume of a cone equals

V2=\frac{1}{3}\pi r^{2} h

In this example

r=8\ units \\ l=17\ units \\ h=?

Use the Pythagorean Theorem to determine the height h

h^{2} =l^{2}-r^{2}\\ h^{2} =17^{2}-8^{2}\\ h^{2}=225\\ h=15\ units

V2=\frac{1}{3}\pi 8^{2} 15\\ \\ V2=320\pi \ units^{3}

Step 3

Calculate the empty volume inside the cylinder

V1-V2=960\pi -320\pi =640\pi \ units^{3}

Thus

the final result is

the empty volume inside the cylinder is 640\pi \ units^{3}

6 0
1 month ago
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You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $1; if
Zina [12044]

Answer: The mean and variance of Y are $0.25 and $6.19 respectively.

Step-by-step explanation:

The scenario is as follows: You and a friend participate in a game involving tossing a fair coin.

The sample space for tossing two coins is {TT, HT, TH, HH}

Let Y represent the earnings from one round of the game.

If both faces are heads, you win $1; therefore, P(Y=1)=P(TT)=\dfrac{1}{4}=0.25

You win $6 if both faces are heads, so P(Y=6)=P(HH)=\dfrac{1}{4}=0.25

If the faces do not match, you lose $3 which means P(Y=1)=P(TH, HT)=\dfrac{2}{4}=0.50

To find the expected value to win: E(Y)=\sum_{i=1}^{i=3} y_ip(y_1)

=1\times0.25+6\times0.25+(-3)\times0.50=0.25

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E(Y^2)=\sum_{i=1}^{i=3} y_i^2p(y_i)\\\\=1^2\times0.25+6^1\times0.25+(-3)^2\times0.5\\\\=0.25+1.5+4.5=6.25

Variance = E[Y^2]-E(Y)^2

=6.25-(0.25)^2=6.25-0.0625=6.1875\approx6.19

Therefore, variance of Y = $ 6.19

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19 days ago
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The minimum distance is the same from both points because their lengths are equal.
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