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Aleksandr
1 month ago
14

gavin is making cranberry lemonade. he wants to make a total of 6 cups. he needs to use 3 times as much lemonade as cranberry ju

ice. how much of each type of juice should he use? if l = cups of lemonade, and c= cups of cranberry, write the equations that you used.
Mathematics
1 answer:
Svet_ta [12.7K]1 month ago
4 0

Answer:

3l= c

Step-by-step explanation:

This requires using 3 cups of cranberry juice, along with 1 cup of lemonade.

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The result is calculated as 10 multiplied by 8 multiplied by 5, which equals 400.
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x2y - 2xy - 24y = y(x2 - 2x - 24) What is the completely factored form of x2y – 2xy – 24y? (xy + 4)(x – 6) xy(x + 4)(x – 6) y(x
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We start with

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Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 emp
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Answer:

a) The likelihood that none of the sampled employees are from the Hawaii plant is 1.74%.

b) The chance that exactly 1 employee from the sample is found working in the Hawaii plant is 8.70%.

c) There is an 89.56% chance that 2 or more employees in the sample are from the Hawaii plant.

d) The probability that 9 employees from the sample are working at the Texas plant is 8.70%.

Step-by-step explanation:

Each employee has two potential employment locations: either Texas or Hawaii. Thus, the binomial probability distribution can be utilized to solve this scenario.

Binomial probability distribution

This distribution defines the probability of achieving exactly x successes in n trials where there are only two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

Here, C_{n,x} denotes the number of ways to choose x objects from a set of n, represented by the subsequent formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of success occurring.

In this context, we know:

The sample comprises 10 employees, therefore n = 10.

a. Calculate the probability that none of the sampled employees are from the Hawaii plant (to 4 decimals)?

Given that 20 out of 60 employees are based in Hawaii:

p = \frac{20}{60} = 0.333

We aim to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.333)^{0}.(0.667)^{10} = 0.0174

Thus, the likelihood that none in the sample are from Hawaii stands at 1.74%.

b. Calculate the probability that 1 employee from the sample is from the Hawaii plant?

This is represented as P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.333)^{1}.(0.667)^{9} = 0.0870

Therefore, there is an 8.70% possibility that 1 employee in the sample comes from Hawaii.

c. Calculate the probability that 2 or more employees in the sample are from the Hawaii plant?

We can observe two scenarios: either fewer than 2 employees are from Hawaii or 2 and beyond. The combined probabilities equal decimal 1. So:

P(X < 2) + P(X \geq 2) = 1

We seek to find P(X \geq 2).

P(X \geq 2) = 1 - P(X < 2)

From problems a and b, we possess values for both probabilities.

P(X < 2) = P(X = 0) + P(X = 1) = 0.0174 + 0.0870 = 0.1044

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1044 = 0.8956

Accordingly, the chance that 2 or more employees in this sample operate at the Hawaii plant is 89.56%.

d. Calculate the likelihood that 9 employees in the sample are working at the Texas plant?

This corresponds to the probability found in part b for 1 employee working in Hawaii.

Consequently, there is an 8.70% chance that 9 employees belong to the Texas plant.

6 0
3 months ago
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