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Rama09
28 days ago
11

Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combinin

g the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.Note: This page converts rgb values into colors.
the answer:
#include
using namespace std;
int main() {
int red;
int green;
int blue;
cin >> red >> green >> blue;
if ((red <= green) && (red <= blue)) {
cout << red;
}
else if ((green <= red) && (green <= blue)) {
cout << green;
}
else {
cout << blue;
}
return 0;
}
Computers and Technology
1 answer:
Rzqust [1K]28 days ago
5 0

Answer:

Below is the code related to the question:

#include<iostream>//header file declaration

using namespace std;// utilizing the namespace

int main()//entry point of the program

{

int red, green, blue, x;//integer variables declaration

cin>> red >> green >> blue;//input method for values

if(red<green && red<blue)//checking if red is less than both green and blue

{

x = red;//storing red value in x

}

else if(green<blue)//else if checking if green is less than blue

{

x= green; //assigning green value to x

}

else//the default case

{

x=blue;//storing blue value in x

}

red -= x;//subtracting x from red

green -=x; //subtracting x from green

blue -= x;//subtracting x from blue

cout<<red<<" "<<green<<" "<<blue;//outputting the values

return 0;

}

Output:

130 50 130

80 0 80

Explanation:

In the provided code, within the main function, four integers "red, green, blue, and x" are declared, where "red, green, and blue" serve to get user input. Next, a conditional structure checks if the value of red is smaller compared to both "green and blue". If so, it sets the value of red into "x", otherwise, it proceeds to the else if statement.

  • Here, it checks if green's value is greater than that of blue. If the condition holds true, it stores the value of green in "x".
  • Next, the else clause captures the scenario where the blue value is stored in "x". Finally, the input variables are adjusted by subtracting the value of "x" and displaying the results.
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Sketch the developments in multimedia. What do you expect to be the commercial impact of multimedia in the (near) future?
Natasha_Volkova [1026]

Answer:

Multimedia has become an essential and vital part of various sectors such as healthcare, education, entertainment, and marketing.

Explanation:

In the past, children primarily learned using textbooks, but now they engage with smart boards and other interactive digital devices that provide animated content.

The role of multimedia is crucial in entertainment, where there has been a significant increase in attendance for multimedia events.

Similarly, in the medical field, students can learn more effectively with the use of multimedia tools. Looking ahead, multimedia is expected to draw interest across all disciplines and its future seems promising.

4 0
1 month ago
A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen
Natasha_Volkova [1026]

Answer:

C3H8

Explanation:

Step 1:

Relevant details from the question are noted below:

Mass of the alkane is 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Convert to the appropriate units.

For Volume:

1000mL = 1L

So, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature in Kelvin = Temperature in Celsius + 273

Temperature in Celsius = 28°C

Temperature in Kelvin = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

So, 741 mmHg = 741/760 = 0.975atm

Step 3:

Calculate the moles of the alkane.

The moles of the alkane can be found using the ideal gas equation, presented below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of moles (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 moles

Step 4:

Calculate the alkane’s molar mass.

Mass of alkane = 1.17g

Number of moles = 0.0266moles

Molar Mass =?

Number of moles = Mass/Molar Mass

Molar Mass = Mass/Number of moles

Molar Mass of alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determine the molecular formula of the alkane.

This is based on:

The general formula for alkanes is CnH2n+2

To find the molecular formula, we start with n = 1, 2, 3, etc., until we find the molar mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

It can be observed that for n equal to 3, the molar mass is 44g/mol.

Thus, the molecular formula of the alkane is C3H8.

7 0
2 months ago
Your computer uses 4 bits to represent decimal numbers (0, 1, 2, 3 and so on) in binary. What is the SMALLEST number for which a
amid [951]

Response: C

Clarification:

The reason is that four binary bits are insufficient to represent the number sixteen. The maximum is 15.

3 0
2 months ago
Assume that you are testing the Orders database introduced in Watt (2014) - Appendix C. Discuss the problems and possible conseq
ivann1987 [1066]

Answer:

129 \frac{2}{?} 23.4. \div 164 \times 5y1 +. \\.00487ggh

6 0
1 month ago
Declare a constant named YEAR, and initialize YEAR with the value 2050. Edit the statement myNewAge = myCurrentAge + (2050 − cur
amid [951]

Answer:

The following changes will be implemented to the source code

const int YEAR = 2050;

cout << "I will be " << myNewAge << " in "<<YEAR<<"." << endl;

Explanation:

First, YEAR needs to be defined as a constant integer. This is represented as follows;

const int YEAR = 2050;

This allows us to refer to YEAR throughout the program

Next,

Substitute the following:

cout << "I will be " << myNewAge << " in 2050." << endl;

with

cout << "I will be " << myNewAge << " in "<<YEAR<<"." << endl;

The revised source file is attached;

Download cpp
7 0
2 months ago
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