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Serjik
1 month ago
6

Greenfields is a mail order seed and plant business. The size of orders is uniformly distributed over the interval from $25 to $

80. Use the following random numbers to generate the size of 10 orders. .41 .99 .07 .05 .38 .77 .19 .12 .58 .60 What is the value for the first order size generated randomly based on random number 0.41? What is the value for the last order size generated randomly based on random number 0.60? What is the average order size?
Mathematics
1 answer:
babunello [11.8K]1 month ago
4 0

Answer:

a) 47.55

b) 58

c) 47.88

Step-by-step explanation:

Considering that the order sizes are uniformly distributed across the range

$25 ( a ) to $80 ( b )

a) Calculate the measurement for the initial order size, applying a random number of 0.41

The parameters for the normal distribution are a = 25, b = 80

The size or value of the order is calculated as follows:  = a + random number ( b - a )

                                = 25 + 0.41 ( 80 - 25 )

                                =  47.55

b) The last order's generated value using the random number (0.6)

= a + random number ( b - a )

= 25 + 0.6 ( 80 - 25 )

= 25 + 33 = 58

c) Average order size

= ∑ order 1 + order 2 + ----- + order 10  ) / 10

= (47.55 +...... + 58 ) / 10

= 478.8 / 10 = 47.88

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