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notka56
1 month ago
5

You have $60 and your sister has $120. You are saving $14 per week and your sister is saving $10 per week. How

Mathematics
1 answer:
tester [12.3K]1 month ago
8 0

Response:

15 weeks

$270

Detailed breakdown:

60+14x=120+10x

4x=60

x=15 weeks

total= 60+14*15= $270

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Suppose your statistics professor reports test grades as​ z-scores, and you got a score of 1.57 on an exam. ​a) Write a sentence
tester [12383]

Answer:

a) In this case, we have a z-score of 1.57, characterized as:

z =\frac{x -\mu}{\sigma}

This signifies that our score is 1.57 standard deviations above the average of all test scores.

b) P(Z

Using the normal standard distribution or Excel, we computed:

P(Z

This represents 2.275% of the dataset.

Step-by-step explanation:

Previous concepts

Normal distribution denotes a "probability distribution that is symmetric around the mean, indicating that data close to the mean occurs more frequently than data further from it".

The Z-score serves as "a statistical measurement representing a value's relation to the average (mean) of a set, calculated in terms of standard deviations away from the mean".

Solution to the problem

Part a

For this instance, we hold a z-score of 1.57, which is defined as:

z =\frac{x -\mu}{\sigma}

This shows that our score is 1.57 deviations above the overall test score average.

Part b

A z-score of z=-2 indicates that your friend's score is 2 deviations below the other test scores.

Assuming a normal distribution, we can derive the percentage:

P(Z

Using the normal standard distribution or Excel, we discovered:

P(Z

This represents 2.275% of the data.

6 0
3 months ago
A survey asked students whether they have any siblings and pets. the survey data are shown in the relative frequency table.
PIT_PIT [12445]

Response:

The probability that a student has a pet, given they do not have any siblings is:

Option: D ( 60%)

Step-by-step breakdown:

Let A represent the situation where a student lacks a sibling.

Let B signify the occurrence that a student has a pet.

Consequently, A∩B refers to the event in which a student is without siblings but possesses a pet.

Let P denote the chance of an event happening.

We need to determine:

P(B|A)

From our knowledge:

P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}

From the data provided:

P(A)=0.25

and P(A∩B)=0.15

Thus,

P(B|A)=\dfrac{0.15}{0.25}\\\\P(B|A)=\dfrac{3}{5}\\\\P(B|A)=0.6

which expressed as a percentage is:

0.6\times 100=60\%

Therefore, the probability is:

60%

5 0
2 months ago
. The ABC Ink Company is a small family owned company that sells packages of ink cartridge refills for smartpens. The Xavier set
Inessa [12570]
In order to utilize the leftover stock properly, the company must package the Zena's product, committing to include one of Xavier's product in each bundle. The Xavier set consists of one blue and one black ink refill, while the Yvonne set comprises two blue, three black, and one red ink refill, whereas the Zena set contains four blue, five black, and one red ink refill. The company has 11 blue, 14 black, and 3 red ink cartridge refills available. Thus, forming equations based on existing inventory would yield the required quantities for optimal packaging without any leftover supplies.
6 0
1 month ago
Alejandro surveyed his classmates to determine who has ever gone surfing and who has ever gone snowboarding. Let A be the event
tester [12383]

Answer:

\text{A and B are independent events}, P(A|B)=P(A)=0.16

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To establish independence between two events, we must understand the concept of independence:

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In this situation, the only selection that aligns with the independence criterion is P(A|B)=P(A)=0.16. Other options do not comply with the independent events definition.

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2 months ago
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Pete is conducting a survey to determine his customers’ overall satisfaction about the quality of his company’s products. He sen
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No.
In order to conduct an analysis like this one, it is essential to select a RANDOM SAMPLE from the entire POPULATION involved in the study. For instance, Pete is attempting to gauge the overall satisfaction of his customers, therefore, he should distribute the surveys to a randomly chosen group of customers rather than only targeting those who have bought the most items. Doing so will yield results that are more REPRESENTATIVE of the overall customer satisfaction. If he limits the surveys to those customers who have purchased the most, he is likely to see inflated satisfaction levels, which would not truly reflect the general sentiment of all customers.
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3 months ago
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