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15 days ago

N(17+x)=34x−r I need to solve for x

Mathematics

2 answers:

Svet_ta [4.3K]15 days ago

4 0

Answer:

The solution for x is shown here: $x= \frac{17N+r}{34-N}$

Explanation:

Given: $N(17+x)=34x-r$

The distributive property allows multiplying a single term by each term within a parenthesis individually.

If $a\cdot(b+c) =a\cdot b + a\cdot c$ ,

applying the distributive property to the left side produces:

$N\cdot 17+N\cdot x = 34x-r$ or $17N+Nx = 34x-r$

The addition property of equality means adding the same quantity to both sides maintains the equation's balance.

Add r to both sides:

$17N+Nx+r=34x-r+r$

Simplify:

$17N+Nx+r=34x$

The subtraction property of equality allows subtracting the same value from both sides.

Subtract Nx from each side:

$17N+Nx+r-Nx=34x-Nx$

Simplify:

$17N+r=34x-Nx$

$17N+r=x(34-N)$

The division property of equality permits dividing both sides by the same nonzero number.

Divide both sides by (34-N):

$\frac{17N+r}{34-N}= \frac{x(34-N)}{34-N}$

Upon simplification:

$x= \frac{17N+r}{34-N}$

tester [3.9K]15 days ago

3 0

The value of x equals (17N + r) divided by (34 minus N).

Starting from N(17 + x) = 34x - r,

expand left side: 17N + Nx = 34x - r

Group the x terms together.

The expression rearranged is (17N + r) over (34 - N).

Thus, the solution is

(17N + r) / (34 - N).

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