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ankoles
2 months ago
11

Hannah reads at a constant rate of 333 pages every 888 minutes.

Mathematics
1 answer:
Leona [12.6K]2 months ago
6 0

Respuesta:

333/888

Explicación paso a paso:

Explicación paso a paso:

Dado que, él lee 3 páginas cada 8 minutos.

Esto significa que 8 minutos = 3 páginas,

⇒ 1 minuto = 3/8 páginas,

Además, está leyendo a una velocidad constante,[

Aquí, p representa el número de páginas leídas en m minutos,

Que es la relación requerida entre el número de páginas que ella lee (p) y el número de minutos que pasa leyendo (m).

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Rework problem 4 from section 3.2 of your text, involving sets E and F. Suppose for this problem that Pr[E]=1/12, Pr[F]=1/12, an
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The corresponding Venn Diagram for this issue is depicted below

P(E|F) and P(F|E) denote the conditional probabilities.

P(E|F) is calculated as P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is determined by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1

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2 months ago
Tickets for a concert were \$5$5dollar sign, 5 for each child and \$8$8dollar sign, 8 for each adult. At one of the concerts, ea
Svet_ta [12734]

Answer:

Step-by-step explanation:

Let c denote the total number of children present at the concert.

Let a indicate the total number of adults who attended the concert.

During one concert, every adult accompanied 4 children, while 10 children came unaccompanied. Therefore, the equation representing the children is

c = 4a + 10

The prices for tickets were set at $5 for each child and $8 for every adult. The overall revenue from ticket sales amounted to $1730. This generates the equation

5c + 8a = 1730

Consequently, the set of equations to find the number of children, c, and adults, a, that were present at the concert is

c = 4a + 10

5c + 8a = 1730

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1 month ago
A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. A cylind
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Answer:

B

Detailed breakdown:

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1 month ago
Read 2 more answers
Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
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The response is:

The 95% CI for the variance in means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Here’s a detailed explanation:

The inquiry lacks sufficient information:

"Determine a 95% confidence interval on the difference in absorbency means from two manufacturing methods. Assume standard deviations derived from the data. Round to two decimal places."

For process 1:

- Sample size: 10

- Mean: 200

- SD: 15

For process 2:

- Sample size:  4

- Mean: 300

- SD: 50

The difference between sample means is:

M_d=M_1-M_2=200-300=-100

The estimated standard deviation is:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom calculated are:

df=n_1+n_2-2=10+4-2=12

For a 95% confidence interval, the t-value for 12 degrees of freedom is t=±2.179.

So, the confidence interval can be expressed as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

8 0
1 month ago
An architect is designing a rectangular house that is 60 feet long and 40 feet wide. He uses of the area for the 1/4 living room
zzz [12365]

Response:

6o×40=2400

area 1/4=2400÷4=600

area 1/6=600÷6=100

(d)=100 ft2

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1 month ago
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