According to the rule of 72,
72/rate=time
72÷9.6=7.5 years
An alternative method for resolution using the main formula
2300=1150(1+0.096/4)^4t
Isolate t
t=((log(2,300÷1,150)÷log(1+(0.096÷4))÷4))=7.31 years
I hope this is helpful:-)
Answer:
The resulting value is 2.381
Step-by-step explanation:
Using the information presented in the question, we will calculate the evidence supporting the professor's hypothesis
Given that:
x₁ = 74,
n₁ = 36
s₁ = 8
x₂ = 68
n₂ = 36
s₂ = 10
The hypotheses can be outlined as:
The critical value is t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀₁
thus,
t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀ = 2.381
This implies a range of -2.381 to 2.381
Thus, we can support the professor's assertion.
The cubic equation formed is L^3 - 52L +144 = 0. Dimensions: Length = 4 inches, Width = 2 inches, Height = 3 inches. To determine this, let L be the length, W the width, and H the height. The box volume is 24 cubic inches, and its total surface area is 52 sq. inches. Setting W = L/2 leads to Volume = L * W * H, thus substituting W gives us the equation 0.5L^2 * H = 24 resulting in H = 48/L^2. The surface area equation simplifies to (L*W) + (L+H) + (W+H) = 26. Introducing W = 0.5L yields 0.5L^2 + 1.5LH = 26. Substituting H into this gives 0.5L^2 + 72/L = 26. Multiplying throughout by L to eliminate denominators yields 0.5L^3 - 26L + 72 = 0. After multiplying through by 2: L^3 - 52L +144 = 0. Testing L=4 confirms a factor, thus Length (L) = 4 inches, and subsequently, W and H calculate to 2 inches and 3 inches respectively.