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vlabodo
2 months ago
8

A box with rectangular sides has width twice the length of the base. The volume is 24 cubic inches and the total surface area of

all six sides is 52 square inches. Write down a (cubic) equation whose solution is the length of the box.
Mathematics
1 answer:
lawyer [12.5K]2 months ago
4 0
The cubic equation formed is L^3 - 52L +144 = 0. Dimensions: Length = 4 inches, Width = 2 inches, Height = 3 inches. To determine this, let L be the length, W the width, and H the height. The box volume is 24 cubic inches, and its total surface area is 52 sq. inches. Setting W = L/2 leads to Volume = L * W * H, thus substituting W gives us the equation 0.5L^2 * H = 24 resulting in H = 48/L^2. The surface area equation simplifies to (L*W) + (L+H) + (W+H) = 26. Introducing W = 0.5L yields 0.5L^2 + 1.5LH = 26. Substituting H into this gives 0.5L^2 + 72/L = 26. Multiplying throughout by L to eliminate denominators yields 0.5L^3 - 26L + 72 = 0. After multiplying through by 2: L^3 - 52L +144 = 0. Testing L=4 confirms a factor, thus Length (L) = 4 inches, and subsequently, W and H calculate to 2 inches and 3 inches respectively.
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Answer:

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5 0
3 months ago
Read 2 more answers
rectangle abcd is similar to rectangle pqrs. given ab=14 cm, BC=8cm and pq=21cm, calculate the length of QR
babunello [11817]
QR is 12, as you establish a proportion: 21/14 = x/8, then cross-multiply to obtain 14x = 168, which you solve by dividing to find x = 12.
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An automobile manufacturer sold 30,000 new cars, one to each of 30,000 customers, in a certain year. The manufacturer was intere
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A) To establish a sampling plan, follow these 5 steps:
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4 0
3 months ago
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