We have to calculate the result of the division problem.
To determine the result, long division will be employed.
)
Initially, we quotient with x since 
fits into 
, x times.
Thus, we have:
)(x
After subtraction, we obtain:
We can see that fits into 
, -2 times; therefore, the next addition to the quotient will be -2. This results in a final quotient of (x-2).
Answers:
The vertical asymptote is located at x = 0
The horizontal asymptote is identified as y = 0
The domain encompasses all real nonzero values
The range includes all nonzero real values
EXPLANATIONS
Given the function f(x) = c/x
c represents a non-zero real number
To find the vertical asymptote, we equate the denominator to 0
f(x)=c/x
The denominator is x
Setting x = 0
To establish the horizontal asymptote, we must compare the polynomial degrees in the numerator and denominator.
The numerator contains a polynomial of degree zero
While the denominator has a polynomial of degree one.
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Since the numerator's polynomial degree is less than that of the denominator, the horizontal asymptote is at y=0.</span>
Because the vertical asymptote is x = 0, the domain consists of all real numbers except x = 0
With the horizontal asymptote being y = 0, the range is all real numbers excluding y = 0
First, combine the solution and salt: 120 liters + 80 liters = 200 liters. The percentages average out: 5% + 15% = 20%. Therefore, the ratio is 20:200, leading to a concentration calculation of 20/200 = 0.10. Ultimately, the final concentration is 10% salt.
F(x) = 1,000. 70n - 400 = 1,000. 70n = 1,000 + 400. 70n = 1,400. n = 1,400/70. n = 20. The instructor requires 20 students.
Zx = 5g(2x - c) Apply the Distributive Property
zx = 10gx - 5cg Subtract 10gx from each side
zx - 10gx = -5cg Factor x out
x (z - 10g) = -5cg Divide by (z - 10g)
x = 
