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Juli2301
2 months ago
8

Which portrays inadequate data? Geoff uses another classmate’s data because he forgot to record his own experiment’s temperature

readings. Shelby accidentally switches steps 3 and 4 while writing her laboratory procedure. Rupal determines aluminum is the most reactive metal by completing only half of her experiment. Juan records the density of acetone in grams per cubic liters instead of grams per milliliters.
Biology
2 answers:
-BARSIC- [2.5K]2 months ago
7 0

Answer:

Option C is the correct selection.

Explanation:

  • Rupal concludes that aluminum might be the most potent oxidizer by only completing a quarter of her research. Due to the incomplete nature of her study, she ended up with inadequate information and thus arrived at flawed findings.
  • The oxidizing agent that is more active in the excitation prequel list is potassium, not aluminum (even though aluminum is known to be a highly effective metal and oxidant).

Other available choices do not pertain to the scenario described. Therefore, Option C is deemed the suitable answer.

Rainbow [2.3K]2 months ago
4 0

The answer is option C. Rupal concludes that aluminum is the most reactive metal after completing only a fraction of her analysis.

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In an animal cell, which two cell structures do newly-synthesised enzymes have to pass through to reach the external environment
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Answer:

Ribosomes, Cell membrane

Explanation:

Ribosomes serve as the sites where proteins are synthesized. Therefore, they are referred to as the protein production factories of a cell. Since enzymes are a type of protein, their synthesis occurs within ribosomes.

The cell membrane functions as the boundary that surrounds the cell or separates it from its environment.

To exit the cell and enter the external environment, an enzyme must navigate through both the ribosomes and the cell membrane.

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1 month ago
"Choanoflagellates are protists. The other four taxa are animals. Which phylogenetic tree highlights the most recent common ance
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Answer:

Constructing phylogenetic trees using molecular data

A transformative tool for phylogenetic analysis is DNA sequencing. This method allows us to compare the sequences of orthologous (evolutionarily related) genes or proteins instead of relying solely on the physical or behavioral traits of organisms.

The fundamental concept behind such comparisons is akin to our previous discussion: there is a common ancestor for the DNA or protein sequence, and it may have undergone changes throughout evolutionary history. However, a gene or protein isn't limited to a singular characteristic that exists in two forms.

Instead, every nucleotide in a gene or each amino acid in a protein can be considered an individual feature that can mutate into multiple forms (e.g., A, T, C, or G for nucleotides). Thus, a gene consisting of 300 nucleotides could be interpreted as having 300 distinct features present in 4 states. The data gleaned from sequence analyses—and consequently, the detail we can achieve in a phylogenetic tree—is significantly greater than when we analyze physical characteristics.

To interpret sequence data and uncover the most likely phylogenetic tree, biologists often employ computer software and statistical algorithms. Generally, when sequences of a gene or protein are compared among species:

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3 0
2 months ago
Hydrolytic enzymes must be segregated and packaged to prevent general destruction of cellular components. Which of the following
inysia [2303]

Answer:

B) Lysosome

Explanation:

Lysosomes are organelles within eukaryotic cells, characterized by a covering of double membranes and an internal composition of hydrolytic enzymes. These enzymes, commonly referred to as digestive enzymes, play important roles in catalyzing the breakdown of proteins and various complex molecules. Examples of hydrolytic enzymes located within lysosomes include proteases, glycosidases, and phosphatases.

6 0
1 month ago
Amphiarthrodial joints display ___ movement than synarthrodial joints.
garik1379 [2080]
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1 month ago
Given the following genotypes for two parents, AABBCc × AabbCc, assume that all traits exhibit simple dominance and independent
lana [2441]
Given the conditions referenced in the question, which include independent assortment and simple dominance, crossing these two parent genotypes will yield an expected 75% of the offspring resembling the AABBCc genotype parent. To elaborate, independent assortment is when an organism's alleles for a trait separate independently during meiosis, while simple dominance refers to the effect of dominant and recessive alleles for a trait—with the trait appearing if at least one dominant allele is present. Understanding these principles allows us to solve the problem. For Parent 1, the genotype is AABBCc, and the possible allele combinations produced are ABC and ABc. For Parent 2, with a genotype of AabbCc, the assortments include AbC, Abc, abC, and abc. After using a Punnett square to combine these alleles, the resulting genotypes are AABbCC, AABbCc, AaBbCC, AaBbCc, AABbCc, AABbcc, AaBbCc, and AaBbcc, leading to a genotypic ratio of 1AABbCC: 2AABbCc: 1AABbcc: 1AaBbCC: 2AaBbCc: 1AaBbcc. The phenotypic ratio expected from this cross is 6ABC and 2ABc, thus 75% of the offspring should resemble the first parent, calculated by (6/8) x 100 = 75%.
5 0
1 month ago
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