She ought to select the monthly plan for unlimited movies instead of paying $2.99 per film. This choice is advisable because if she continues paying this amount for each individual movie, her total monthly costs will rise significantly. For example, if she has 8 days off in a month (on Saturdays and Sundays) and pays for each film on those days, the total expense would exceed that of the unlimited monthly plan priced at $7.99. And that doesn't include other potential viewing days or any public holidays that could allow her to watch more movies.
1,107 cc
The scanning consists of 10 intervals:
[0,1.5), [1.5,3), [3,4.5), [4.5,6), [6,7.5), [7.5,9), [9,10.5), [10.5,12), [12,13.5), [13.5,15)
To estimate the volume using the Midpoint Rule, n should be set to 10.
Given that we will use n=5, we will split the range [0,15] into five intervals of lengths 3 each:
[0,3], [3,6], [6,9], [9,12], [12,15] and calculate their midpoints:
1.5, 4.5, 7.5, 10.5, and 13.5.
Next, we will determine the volume V from the five cylinders, where each has a height h=3 and the base area A corresponds to the calculated midpoints' intervals:
Cylinder 1
Midpoint=1.5, corresponding to the 2nd interval
A = 18, V= height * area of the base = 18*3 = 54 cc
Cylinder 2
Midpoint=4.5, corresponding to the 4th interval
A = 78, V= height * area of the base = 78*3 = 234 cc
Cylinder 3
Midpoint=7.5, corresponding to the 6th interval
A = 106, V= height * area of the base = 106*3 = 318 cc
Cylinder 4
Midpoint=10.5, corresponding to the 8th interval
A = 129, V= height * area of the base = 129*3 = 387 cc
Cylinder 5
Midpoint=13.5, corresponding to the 10th interval
A = 38, V= height * area of the base = 38*3 = 114 cc
Thus, the estimated volume is
54 + 234 + 318 + 387 + 114 = 1,107
The solution to your inquiry is that there were 88 children. The total number of individuals was 188, the total expenditure amounted to $5040, and there were 12 more adults than there were seniors. The equations can be structured as follows: a + c = 188 (Equation I) and a = c + 12 (Equation II). By substituting Equation II into Equation I, we find that (c + 12) + c = 188, leading to 2c + 12 = 188. Solving for c, we find c = 88.
