To determine the rates at which the inlet and outlet pipes fill and empty the reservoir, we remember that work done equals rate multiplied by time. Let’s denote the inlet rate as i and for the outlet pipe as 0. Therefore,
i(24) = 1
o(28) = 1
In this context, the '1' represents the total number of reservoirs, since the problem states the time needed for each pipe to either fill or empty a singular reservoir. Solving for rates yields:
i = 1/24 reservoirs/hour
o = 1/28 reservoirs/hour
Over the first six hours, the inlet pipe fills (1/24)(6) = 1/4 reservoirs and during the same period, the outlet pipe empties (1/28)(6) = 3/14 reservoirs. To calculate the net volume of the reservoir filled, we subtract the emptying total from the filling total:
1/4 - 3/14 = 1/28 reservoirs (note that if emptying exceeds filling, a negative value results. In such cases, treat that negative value as zero, indicating that the outlet rate surpasses the inlet rate, leading to an empty reservoir).
Now we need to find out how long it will take to fill up one reservoir since we’ve already partially filled 1/28 of it, after closing the outlet pipe. In simpler terms, we need to determine the time required for the inlet pipe to finish filling the remaining 27/28 of the reservoir. Fortunately, we have already established the filling rate for the inlet pipe, leading to the equation:
(1/24)t = 27/28
Solving for t gives us 23.14 hours. Remember to add the initial 6 hours to this result since the question seeks the total time. Thus, the final total is 29.14 hours.
Please ask me any questions you may have!
The least number of times that two planes can cross is zero, since parallel planes do not intersect. A good example would be a floor and a ceiling, which run parallel, hence they do not meet. Conversely, if two planes occupy the same space, they can intersect at infinitely many points, as could happen with a line within that plane.
Answer:
On a coordinate grid, a triangle is defined by the points R' (1, 2), S' (3, -1), T' (7, 1)
Step-by-step explanation:
We can interpret the coordinates of the triangle's vertices as...
R(-2, 1), S(1, 3), T(-1, 7)
Applying the transformation (x, y) ⇒ (y, -x), these coordinates change to...
R'(1, 2), S'(3, -1), T'(7, 1) . . . . . (this corresponds to the first option)
Answer:
The ratio 
corresponds to the tangent of ∠I.
Step-by-step explanation:
Let’s revisit the trigonometric ratios:
For triangle HIJ
∵ m∠J = 90°
- The hypotenuse is the side opposite the right angle.
So, HI is the hypotenuse.
∵ HJ = 3 units
∵ IH = 5 units
- We’ll apply the Pythagorean Theorem to solve for HJ.
∵ (HJ)² + (IJ)² = (IH)²
∴ 3² + (IJ)² = 5²
∴ 9 + (IJ)² = 25
- Subtract 9 from both sides.
∴ (IJ)² = 16
- Taking the square root on both sides gives:
∴ IJ = 4 units
To determine the tangent of ∠I, identify the sides that are opposite and adjacent to it.
∵ HJ is opposite to ∠I
∵ IJ is adjacent to ∠I
- Utilizing the rule of tan above:
∴ tan(∠I) = 
∴ tan(∠I) =
The ratio indicates the tangent of ∠I.
Answer:
3x = 12
x = 4
Step-by-step explanation:
The equation indicates that the distance to the dance class is three times that to her home, and when multiplied by "x", it reveals how much farther 3 is from 12. Consequently, if you evaluate the expression, the distance to the dance class is four times greater than that to her music class.
