Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a

Question

Taya2010

3 months ago

8

Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a

nd y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 StartRoot 2 EndRoot Over 4 EndFraction

Mathematics

2 answers:

babunello [11.8K] · Answer 1 · 2026-02-22T12:33:49+03:00

babunello [11.8K]3 months ago

6 0

Answer:

c

Explicación paso a paso:

Inessa [12.5K] · Answer 2 · 2026-02-22T12:34:39+03:00

Answer:

$y = \frac{3 + 6\sqrt{2} }{4}$ y $y = \frac{3 - 6\sqrt{2} }{4}$

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction

Explicación paso a paso:

La ecuación cuadrática que tenemos es (4y - 3)² = 72

Debemos encontrar el valor de y.

Ahora, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒ $y = \frac{3 + 6\sqrt{2} }{4}$ y $y = \frac{3 - 6\sqrt{2} }{4}$

Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)