Answer:
160/1001, 175/1001
Step-by-step explanation:
i) We calculate:
₈C₁ methods to select 1 new camera from a selection of 8
₆C₃ methods to select 3 refurbished cameras from a selection of 8
₁₄C₄ methods to select 4 cameras from the total of 14 cameras
The probability formula is:
P = ₈C₁ ₆C₃ / ₁₄C₄
P = 8×20 / 1001
P = 160 / 1001
P ≈ 0.160
ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:
P = ₆C₄ / ₁₄C₄
P = 15 / 1001
Therefore, the combined probability is:
P = 160/1001 + 15/1001
P = 175/1001
P ≈ 0.175
Correct question:
An urn holds 3 red and 7 black balls. Players A and B take turns withdrawing balls until a red one is chosen. Calculate the probability that A picks the red ball. (A goes first, followed by B, with no replacement of drawn balls).
Answer:
The likelihood that A picks the red ball is 58.33 %
Step-by-step explanation:
A will select the red ball if it is drawn 1st, 3rd, 5th, or 7th.
1st draw: 9C2
3rd draw: 7C2
5th draw: 5C2
7th draw: 3C2
Calculating for all possible scenarios gives us:
9C2 = (9!) / (7!2!) = 36
7C2 = (7!) / (5!2!) = 21
5C2 = (5!) / (3!2!) = 10
3C2 = (3!) / (2!) = 3
Adding these possibilities results in 36 + 21 + 10 + 3 = 70.
The total outcomes for selecting a red ball = 10C3
10C3 = (10!) / (7!3!)
= 120.
The probability that A selects the red ball is determined by dividing the sum of possible events by the overall outcomes.
P( A selects the red ball) = 70 / 120
= 0.5833
= 58.33 %
Response: (0.8115, 0.8645)
Step-by-step outline:
Define p as the proportion of individuals who leave one space after a sentence.
Provided: Sample size: n= 525
Number of respondents indicating they leave one space: 440
Thus, the sample proportion is: 
The z-score for a 90% confidence interval is: 1.645
The formula for determining the confidence interval:
Consequently, a 90% confidence interval for the proportion of people who leave one space after a period is: (0.8115, 0.8645)
1.44 per kilogram
Multiply 1.3 by 2, then deduct 12.7, and after that, divide the result by 7.
