Answer:
0.40
Step-by-step explanation:
The percentage of members who engage only in long-distance running is 8%
Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08
The percentage of members who participate exclusively in field events is 32%
Thus, the probability of a member competing only in field events is P(B) = 0.32
The percentage of members acting as sprinters is 12%
So, the probability that a member is a sprinter is P(C) = 0.12
We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:
P(A or B) = P(A) + P(B)
Substituting the known values results in:
P(A or B) = 0.08 + 0.32 = 0.40
Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40
A.) P(t) = P0e^(kt)
P(20/60) = 40 e^(20k/60)
80 = 40 e^(k/3)
e^(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)
b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells
d.) Rate of change = e^(8k) = e^(8(3ln(2))) = e^(24ln(2)) = e^(16.6355) = 16777216 cells/hour
e.) P(t) = 40(2)^(3t); t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours
(0,1)(2,7)
Calculating the slope (m) gives: (7-1) / (2-0) = 6/2 = 3
The equation is represented as y = mx + b
where the slope (m) equals 3
Utilizing either of your coordinates... (0,1).... this implies x = 0 and y = 1
Substituting to solve for b, the y-intercept
1 = 3(0) + b
which simplifies to 1 = b
Thus, the equation you seek is: y = 3x + 1....or 3x - y = -1
Answer:
Approximately 59 stacked cups.
Step-by-step explanation:
We have the following measurements:
Height of one cup = 12.5 cm,
Height of two cups stacked = 14 cm,
Height of three cups stacked = 15.5 cm,
...and so on.
This situation can be described by an arithmetic sequence,
12.5, 14, 15.5,....
The first term is defined as a = 12.5,
with a common difference of d = 1.5 cm.
Thus, the height of x stacked cups is given by

As per the problem,
h(x) = 200
⇒ 1.5x + 11 = 200
⇒ 1.5x = 189
⇒ x = 59.3333333333 ≈ 59.
Therefore, you will need approximately 59 stacked cups.