x y
1 290
2 280
3 270
4 260
5 250
6 240
7 230
8 220
9 210
10 200
11 90
12 180
13 170
14 160
15 150
16 140
17 130
18 120
19 110
20 100
21 90
22 80
23 70
24 60
25 50
26 40
27 30
28 20
29 10
30 0
The attached graph shows the moment when his catch surfaced at (35, 0). Given that it ascends consistently, the graph is linear. We need to establish the starting depth before he reeled it in. Using the equation d=rt, where d represents depth, r is the speed, and t is the time, we can find the distance traveled to reach the surface. Setting up the equation yields: d = 0.1(35). This indicates the catch traveled 3.5 m from a starting point of 3.5 m underwater, ascending at a rate of 0.1 m per second.
Greetings:
<span>(4y-3)²=72
4y-3 = </span>±√72
thus, y= (3+√72) /4 or y= (3 - √72) /4
Distance formula:
5 units-4.5 units=0.5 units
Segment LM exceeds segment JK by 0.5 units.
I believe it's around $62, though I'm uncertain. Sorry for the lack of precision, but wish you all the best in life! <3
