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ryzh
11 days ago
15

P=100a÷t solve for a

Mathematics
2 answers:
tester [3.9K]11 days ago
8 0

a=1/100pt is the right solution. Initially, you need to multiply both sides of the equation by t, which results in ⇒ pt=100a. After that, inverting the equation gives ⇒100a=pt. Alternatively, dividing both sides of the equation by one hundred (100) also leads us to \frac{100a}{100}=\frac{pt}{100}. Ultimately, the final answer is a=1/100pt is the result. I hope this offers assistance! Thank you for asking your question, and enjoy your day. -Charlie

Leona [4.1K]11 days ago
6 0
The outcome is 1/100, which indicates one part of a hundred.
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Answer:

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Step-by-step explanation:

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2 days ago
Hope researches the impact of one variable on another. She graphs the data from her research and sees that the data forms a shap
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The correct answer is:

She can ascertain that while there exists an association between the variables, a correlation does not exist, and causation cannot be established.

Explanation:

Due to the arch shape of her graph, it indicates that as one variable varies, the other also changes. This indicates an association exists between these variables.

Nonetheless, given that the graph does not follow a linear pattern, no correlation can be claimed. As there is no correlation, causation cannot be determined.

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12 days ago
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Ben has 400 counters in a bag. He gives 35 of the counters to Sonia 130 of the counters to Phil 75 of the counters to Lance What
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Answer:

2/5

Step-by-step explanation:

By subtracting 130, 35, and 74 from the total of 400, you arrive at 160 left. Next, simplify this fraction by finding the greatest common divisor to get 2/5!

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10 days ago
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Stefan's family rented a rototiller to prepare an area in their backyard for spring planting. The rental company charged an init
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Step-by-step explanation:

Let h denote the hourly rate for the rototiller rental.

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14 days ago
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The weights of soy patties sold by Veggie Burgers Delight are normally distributed. A random sample of 15 patties yields a mean
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Answer:

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549

Step-by-step explanation:

Given data and notation

\bar X=3.8 indicates the sample mean

s=0.5 refers to the sample standard deviation

n=15 is the sample size

\mu_o =4 represents the value we are testing.

\alpha indicates the significance level for the hypothesis test.

t refers to the statistic of interest.

p_v is the p-value for the test (the variable we are interested in).

Formulate the null and alternative hypotheses.

I will set up the hypotheses to verify if the mean weight falls below 4 ounces, formalizing:

Null hypothesis: \mu \geq 68

Alternative hypothesis: \mu < 4

Since our sample size is < 30 and the population standard deviation is unknown, it’s advisable to utilize a t test to compare the actual mean against the reference value, with the statistic calculated as follows:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)

t-test: "This test compares group means and is commonly utilized to determine if the mean is (greater than, less than, or not equal to) a specific value."

Calculate the statistic

We can substitute the provided information into formula (1):

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549 

3 0
5 days ago
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