A rope attached to the top of a tent is staked into the ground.The rope is 4.5 ft long.The angle formed by the rope and the grou

6d + 20b = 150 d=5 b=6

Bart needs to;

Calculate 6(400), 6(10), and 6(2) ⇒ 2nd

Calculate each addend multiplied by 6 ⇒ 4th

Determine the total of (2400 + 60 + 12) ⇒ 5th

Step-by-step breakdown:

We'll review the distributive property

• a(b + c) = ab + ac
• a(b + c + d) = ab + ac + ad

Bart applied place value along with the distributive property to express the

calculation 6(412)

His calculation can be represented as 6(412) = 6(400 + 10 + 2)

We must find out what Bart needs to do to compute the product

∵ 6(412) = 6(400 + 10 + 2)

- Multiply every component inside the brackets by 6 on the right side

∴ 6(400 + 10 + 2) = (6)(400) + (6)(10) + 6(2)

∴ 6(400 + 10 + 2) = 2400 + 60 + 12

∴ He should multiply each addend by 6, then calculate the total of

  (2400 + 60 + 12)

Bart needs to;

Calculate 6(400), 6(10), and 6(2)

Multiply each addend by 6

Compute the total of (2400 + 60 + 12)

Learn more:

You can find additional information regarding place value at

<span>A table representing a function is provided below.
x    1    2    3    4    5
y    1   16  64 256 1,024

According to the data in the table, from x = 2, the value of y can be represented as

which is equivalent to

This indicates an exponential function.

Thus, the </span><span>most accurate description of the function's graph is: "The graph initially appears flat but ascends sharply."</span>

<span>c. demographics based on the details in the population.#9

#10</span><span>b. 81 and 18.</span>

The weight of an orangutan is 64.5 kilograms

Solution:

It is stated that the orangutan's weight is 142 pounds

Additionally,

1 kilogram is approximately 2.2 pounds

We will now convert 142 pounds into kilograms

1 kilogram = 2.2 pounds

As a result, 142 pounds translates to

When rounding to the nearest tenth, we obtain 64.5 kilograms

Therefore the mass of the orangutan is 64.5 kilograms